Answer:
5 J
Explanation:
F = spring force required to stretch the spring = 10 N
x = stretch in the spring = 1 m
k = spring constant of the spring
Spring force is given as
F = k x
Inserting the values
10 = k (1)
k = 10 N/m
W = work done in stretching the spring
Work done is given as
W = (0.5)k x²
Inserting the values
W = (0.5) (10) (1)²
W = 5 J
If you know the real modulus of the cable (Y), the length, and the area (based on the radius), you can compute the spring constant, k = AE/L. Then, if you know the force used, you can compute the displacement, using F = kd, or d = F / k = FL/(AE). Our answer should work out to units of length. So,
d = 803 N * 9.06 m / [pi*(0.574 cm)^2 * 2.0 x 10^11 N/m^2]
d = 3.5 x 10^-8 Nm^3 / (cm^2 * N)
d = 3.5 x 10^-8 m^3 / cm^2 * (100 cm / 1 m)^2
d = 3.5 x 10^-4 m
Answer:
M g H / 2 = M g L / 2 initial potential energy of rod
I ω^2 / 2 = 1/3 M L^2 * ω^2 / 2 kinetic energy attained by rod
M g L / 2 = 1/3 M L^2 * ω^2 / 2
g = 3 L ω^2
ω = (g / (3 L))^1/2
Its b bc its the volume of the sphere
