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3 years ago

The ability to react with air is a

Physics

2 answers:

seraphim [82]3 years ago

7 0

I already said it but its reactivity

uranmaximum [27]3 years ago

3 0

The ANWSER is reactivity .

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(please help ASAP!)

makkiz [27]

Answer:

It's C. Length

Explanation:

Just think of a ruler. Hope I helped! :)

8 0

3 years ago

Read 2 more answers

Two kids are playing tag. The first kid is running at an unknown speed chasing the other. The first kid has a mass of 25 kg and

Monica [59]

Answer:

1mph

Explanation:

3 0

3 years ago

The index of refraction of silicate flint glass for red light is 1.620 and for violet light is 1.660 . A beam of white light in

Sonja [21]

Answer:

10.16 degrees

Explanation:

Apply Snells Law for both wavelenghts

$n_{1}sin\theta_{1} = n_{2}sin\theta_{2}$

For red

(1.620)(sin 25.5) = (1)(sin r)

For red, the angle is 35.45degrees

For violet

(1.660)(sin 25.5) = (1)(sin v)

For violet, the angle is 45.6 degrees

The difference is 45.6- 35.45 = 10.16 degrees

3 0

3 years ago

which of these changes does a submarine encounter as it returns from the bottom of the ocean to the surface of the ocean

fiasKO [112]

a.the amount of sunlight increases.

Explanation:

As a submarine rises to the surface, the change it encounters that is true from the given options is that the amount of sunlight increases.

The bottom of the ocean is dark and receives little to no sunlight due to the scattering of the rays by ocean water.

As the submarine rises, the volume of water column on it decreases and the pressure on it decreases too.
Also, the temperature rises steadily to the surface.

learn more:

Heat and temperature brainly.com/question/914750

#learnwithBrainly

7 0

3 years ago

The planet Mars has a mass of 6.1 × 1023 kg and radius of 3.4 × 106 m. What is the acceleration of an object in free fall near t

Oksanka [162]

The acceleration due to gravity of Mars is $3.5\ m / s^{2}$

<u>Explanation:</u>

As per universal law of gravity, the gravitational force is directly proportional to the product of masses and inversely proportional to the square of the distance between them. But in the present case, the gravity need to be determined between Mars and the object on Mars. Since the mass of Mars is greater than the mass of any object. Thus,

$\text {Gravitational force of planet}=\frac{G M m}{R^{2}}$

Here, G is the gravitational constant, R is the radius of Mars and M, m is the mass of Mars and the object respectively..

Also, according to Newton’s second law of motion, the acceleration of any object will be equal to the ratio of force exerted on it to the mass of the object.

So in order to determine the acceleration due to gravity of Mars, divide the gravitational force of Mars by mass of object on the surface of Mars.

$Acceleration\ due\ to\ gravity\ of\ mars =\frac{\text {Gravitational force of Mars}}{m \text { of object }}$

$Acceleration\ due\ to\ gravity\ of\ mars =\frac{G M m}{R^{2} \times m}=\frac{G M}{R^{2}}$

$\text { Acceleration due to gravity of mars }=\frac{6.67259 \times 10^{-11} \times 6.1 \times 10^{23}}{3.4 \times 3.4 \times 10^{12}}=\frac{40.703 \times 10^{12}}{11.56 \times 10^{12}}$

$\text { Acceleration }=3.5\ \mathrm{m} / \mathrm{s}^{2}$

3 0

3 years ago