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Anton [14]
3 years ago
9

The ability to react with air is a

Physics
2 answers:
seraphim [82]3 years ago
7 0
I already said it but its reactivity
uranmaximum [27]3 years ago
3 0
The ANWSER is reactivity .
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What is the equivalent of 0° C in Kelvin?<br> Help will give brainiest
givi [52]

Answer:

273.15 dat is the answer im pretty sure

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Lance Armstrong bikes at a constant speed up the Col d’Izoard, a famous mountain pass. Assume his teammates do such a good job r
svetoff [14.1K]

Work done against gravity to climb upwards is always stored in the form of gravitational potential energy

so we can say

W = mgh

here h = vertical height raised

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h = 1.79 km

now from above equation

W = (83 kg)(9.81 m/s^2)(1.79 \times 10^3 m)

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3 years ago
Science plz help meeee
Luden [163]

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The difference in these is that the ovary of a fruit can be edible which forms to enclose around seeds while a tree grows up to have a different structure and means of reproduction/

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8 0
2 years ago
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A camera is equipped with a lens with a focal length of 34 cm. When an object 2.4 m (240 cm) away is being photographed, what is
puteri [66]

Answer:

The magnification is -6.05.

Explanation:

Given that,

Focal length = 34 cm

Distance of the image =2.4 m = 240 cm

We need to calculate the distance of the object

\dfrac{1}{u}+\dfrac{1}{v}=\dfrac{1}{f}

Where, u = distance of the object

v = distance of the image

f = focal length

Put the value into the formula

\dfrac{1}{u}=\dfrac{1}{34}-\dfrac{1}{240}

\dfrac{1}{u}=\dfrac{103}{4080}

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The magnification is

m = \dfrac{-v}{u}

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6 0
2 years ago
An object is thrown directly downward from the top of a very tall building. The speed of the object just as it is released is 17
Softa [21]

Answer:

distance cover is  = 102.53 m

Explanation:

Given data:

speed of object is 17.1 m/s

t_1 = 3.32 sec

t_2 = 5.08 sec

from equation of motion we know that

d_1 = vt_1 + \frac{1}{2} gt_1^2

where d_1 is distance covered in time t1

sod_1 = 17.1 \times 3.32 + \frac{1}{2} 9.8 \times 3.32^2=

d_1 = 110.78 m

d_2 = vt_2 + \frac{1}{2} gt_2^2

where d_2 is distance covered in time t2

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d_2 = 213.31 m

distance cover is  = 213.31 - 110.78 = 102.53 m

3 0
3 years ago
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