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IgorLugansk [536]
3 years ago
9

Find the ratio of the effusion rate of hydrogen gas to the effusion rate of krypton gas.

Chemistry
2 answers:
Zielflug [23.3K]3 years ago
6 0

This problem could be solved through the Graham’s law of effusion (also known as law of diffusion). This law states that the ratio of the effusion rate of the first gas and effusion rate of the second gas is equivalent to the square root of the ratio of its molar mass. Thus the answer would be 0.1098. 

ElenaW [278]3 years ago
3 0

Answer:

4.243

Explanation:

The effusion is the movement of the molecules for a hole by a difference of pressure. The effusion rate is inversely proportional to the molar mass of the gas (M), and the ratio of the rates (R) of two gases can be found by Graham' Law:

R1/R2 = (√M2)/(√M1)

Let's call hydrogen gas as 1 (M1 = 2 g/mol), and krypton gas as 2 (M2 = 36 g/mol):

R1/R2 = (√36)/(√2)

R1/R2 = 4.243

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melamori03 [73]

The mass of carbon dioxide that would be needed to weigh is 462 grams.

Given:

10.5 moles of carbon dioxide.

The periodic table

To find:

The mass of carbon dioxide would be needed to weigh out to make 10.5 moles of carbon dioxide.

Solution:

Mass of carbon dioxide needed = m

Moles of carbon dioxide needed = 10.5 mol

The molar mass of carbon dioxide = M

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M = 1\times 12.011 g/mol+2\times 15.999 g/mol\\\\=44.009 g/mol

The moles of carbon dioxide will be given as:

10.5 mol=\frac{m}{44.009 g/mol}\\\\m=10.5 mol\times 44.009 g/mol=462.0945 g\approx 462 g

The mass of carbon dioxide that would be needed to weigh is 462 grams.

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brainly.com/question/2293005?referrer=searchResults

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3 years ago
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3 years ago
What is the molarity of a sodium carbonate solution containing 32.52 g Na2CO3 dissolved in enough water to make 822 ml of soluti
svet-max [94.6K]

The molarity of a Sodium carbonate solution : 0.373 M

<h3>Further explanation</h3>

Given

32.52 g Na₂CO₃

822 ml of solution = 0.822 L

Required

The molarity

Solution

Molarity shows the number of moles of solute in every 1 liter of solution.

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

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8 0
3 years ago
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