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3 years ago

How can you tell that the solution contains a weak acid?

Chemistry

1 answer:

Marrrta [24]3 years ago

7 0

Acids in solution are a source of hydrogen ions, H+. The hydrogen ions are produced when the acid dissociates or breaks down to form ions.

strong acids:

acids completely dissociate into ions in solution. For example, hydrochloric acid is a strong acid. It ionises completely to form hydrogen ions and chloride ions:

HCl(aq) → H+(aq) + Cl-(aq)

nitric acid and sulfuric acid are also strong acids.

weak acids:
acids only partially dissociate in solution. For example, ethanoic acid is a weak acid. It is only partially ionised to form hydrogen ions and ethanoate ions
hope that helps x

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What is the volume of 11.2 g of O2 at 7.78 atm and 415 K?

irina1246 [14]

Answer:

1.53 L

Explanation:

Step 1: Given data

Mass of oxygen (m): 11.2 g

Pressure (P): 7.78 atm

Temperature (T): 415 K

Ideal gas constant (R): 0.0821 atm.L/mol.K

Step 2: Calculate the moles (n) corresponding to 11.2 g of oxygen

The molar mass of oxygen is 32.00 g/mol.

11.2 g × (1 mol/32.00 g) = 0.350 mol

Step 3: Calculate the volume of oxygen

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 0.350 mol × (0.0821 atm.L/mol.K) × 415 K / 7.78 atm

V = 1.53 L

3 0

3 years ago

How many grams of gas must be released from a 32.0 L sample of CO2(g) at STP to reduce the volume to 16.6 L at STP?

Hoochie [10]

Answer:

30.3 g

Explanation:

At STP, 1 mol of any gas will occupy 22.4 L.

With the information above in mind, we calculate how many moles are there in 32.0 L:

32.0 L ÷ 22.4 L/mol = 1.43 mol

Then we calculate how many moles would there be in 16.6 L:

16.6 L ÷ 22.4 L/mol = 0.741 mol

The difference in moles is:

1.43 mol - 0.741 mol = 0.689 mol

Finally we convert 0.689 moles of CO₂ into grams, using its molar mass:

0.689 mol * 44 g/mol = 30.3 g

6 0

2 years ago

7. A bicycle rider is traveling up a hill. When the rider reaches the top of the hill, she

Anna35 [415]

The one in the middle since when ur going down it’s more quicker anc faster .

8 0

3 years ago

A . liquid and solid b. liquid only c. liquid and gas d. gas only

MArishka [77]

c. liquid and gas

Explanation:

its obvious, lol.

4 0

2 years ago

Write the isotopic symbol for the following (show your work) a) An isotope of iodine whose atoms have 78 neutrons b) An isotope

morpeh [17]

Answer:

For a: The isotopic representation of iodine is $_{53}^{131}\textrm{I}$

For b: The isotopic representation of cesium is $_{55}^{137}\textrm{Cs}$

For c: The isotopic representation of strontium is $_{38}^{52}\textrm{Sr}$

Explanation:

The isotopic representation of an atom is: $_Z^A\textrm{X}$

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

For a:

We are given:

Number of neutrons = 78

Atomic number of iodine = 53 = Number of protons

Mass number = 53 + 78 = 131

Thus, the isotopic representation of iodine is $_{53}^{131}\textrm{I}$

For b:

We are given:

Number of neutrons = 82

Atomic number of cesium = 55 = Number of protons

Mass number = 55 + 82 = 137

Thus, the isotopic representation of cesium is $_{55}^{137}\textrm{Cs}$

For c:

We are given:

Number of neutrons = 52

Atomic number of strontium = 38 = Number of protons

Mass number = 38 + 52 = 90

Thus, the isotopic representation of strontium is $_{38}^{52}\textrm{Sr}$

3 0

3 years ago