Answer:
After 48.84 s, 18.1% of the reactant will remain.
Explanation:
Given that:
The rate constant, k = 0.0350 s⁻¹
Using integrated rate law for first order kinetics as:
Where,
is the concentration at time t
is the initial concentration
Given:
18.1 % of the reactant remain which means that 0.181 of is remained. So,
= 0.181
t = ?
t = 48.84 s
<u>After 48.84 s, 18.1% of the reactant will remain.</u>
Answer:
23 g of Zn will produce 0.352 mole of zinc chloride.
Explanation:
Given data:
mass of Zn = 23 g
Moles of ZnCl = ?
Solution:
Chemical equation:
2Zn + CuCl₂ → 2ZnCl + Cu
Number of moles of Zn:
<em>Number of moles of Zn = mass/ molar mass</em>
Number of moles of Zn = 23 g / 65.38 g/mol
Number of moles of Zn = 0.352 mol
now we will compare the moles of ZnCl with Zn because it is limiting reactant.
Zn : ZnCl
2 : 2
0.352 : 0.352
So 23 g of Zn will produce 0.352 mole of zinc chloride.
A g/mol. Because your dealing with mass and finding the mass of a mole, so it's grams per mole