To determine the quantity of pure CaCl2 from the given amount of CaCl2.9H2O, we use the ratio of CaCl2 to CaCl2.9H2O. From the formula the ratio would 1 is to 1 We calculate as follows:
7.5 g CaCl2.9H2O (1 mol / 273.1215 g) ( 1 mol CaCl2 / 1 mol CaCl2.9H2O ) ( <span>110.98 g / 1 mol ) = 3.05 g CaCl2
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Answer:
[OH]- = 501.187 M
Explanation:
First, the given Ca(OH)2 is a base and not an acid. Therefore, we cannot do the calculations based on the pH vale. We need to get the pOH value.
pH + pOH = 14
11.3 + pOH = 14
pOH = 14 - 11.3 = 2.7
Now, pOH is calculated as follows:
pOH = -log [OH]
This means that:
2.7 = - log [OH]
[OH]- = 10^(2.7)
[OH]- = 501.187 M
Hope this helps :)
Answer:
the rate of a nuclear reaction is increased by the addition of a catalyst.
Explanation:-
Catalysts are substances that increase the speed of ordinary chemical reactions. Ordinary chemical reactions involve electrons. But a nuclear reaction involves only the nucleus. Hence catalysts cannot increase the rate of a nuclear reaction.
The chemical state of the atom depends on the electrons of the atom. Hence a nuclear reaction is unaffected by the chemical state of the atoms involved.
Isotopes have different mass number. So the nucleus is different. Hence nuclear reactions of the same element vary according to which isotope is involved.
In nuclear reactions energy release is given by E= mc 
where c is the speed of light. Hence energy changes in nuclear reactions are much greater than in ordinary chemical reactions.
It would be C bc you are rounding up
