Everything that can be measured is made up of _____ and that is made up of small units called ____

the diameter of a hydrogen atom is about 1.05 cross times 10 to the power of negative 10 end exponentmeters. a protein molecule

Leni [432]

As a result, the protein molecule is 315 x 10^-9 metres long.

<h3>What does a hydrogen atom contain?</h3>

The hydrogen atom is the most fundamental of all atoms because it just contains one proton and one electron.
In addition to this most common isotope, the hydrogen atom can also be found in protium, deuterium, and tritium.
Hydrogen, denoted by the letter H, has the first atomic number among the lightest elements.

<h3>How do you describe a hydrogen atom?</h3>

There are three known hydrogen isotopes.
Hydrogen has isotopes with masses of 1, 2, and 3, with mass 1 being the most common.
This isotope is also referred to as protium and hydrogen in everyday language (symbol H, or 1H).

learn more about hydrogen atom here

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4 0

1 year ago

What is the edge length of a 377-g iron cube? (The density of iron is 7.86 g/cm^3, and the volume of a cube is equal to the edge

VashaNatasha [74]

Answer:3.50 cm

Explanation:

6 0

2 years ago

Read 2 more answers

What is the difference in uniformity between heterogeneous and homogeneous mixtures?

Aneli [31]

Answer:

The correct answer according to the uniformity the difference is whether you can distinguish more than one part in the mixture.

Explanation:

A homogeneous mixture is one in which with the naked eye or with a microscope no different parts can be distinguished. Its composition and properties are the same at all points, the substance is uniform.

In a heterogeneous mixture, we can observe different parts. Its composition is variable. It can be broken down into simpler substances by physical processes. The substance, in this case, is not uniform.

Have a nice day!

4 0

3 years ago

Some students were investigating the

nordsb [41]

Answer:

I am a grade six student but I am very interested in chemistry

Explanation:

I sorry but this is NOT chemistry

5 0

2 years ago

Read 2 more answers

A solution contains 0.0440 M Ca2 and 0.0940 M Ag. If solid Na3PO4 is added to this mixture, which of the phosphate species would

Olenka [21]

Answer:

C. $Ca_3(PO_4)_2$ will precipitate out first

the percentage of $Ca^{2+}$ remaining = 12.86%

Explanation:

Given that:

A solution contains:

$[Ca^{2+}] = 0.0440 \ M$

$[Ag^+] = 0.0940 \ M$

From the list of options , Let find the dissociation of $Ag_3PO_4$

$Ag_3PO_4 \to Ag^{3+} + PO_4^{3-}$

where;

Solubility product constant Ksp of $Ag_3PO_4$ is $8.89 \times 10^{-17}$

Thus;

$Ksp = [Ag^+]^3[PO_4^{3-}]$

replacing the known values in order to determine the unknown ; we have :

$8.89 \times 10 ^{-17} = (0.0940)^3[PO_4^{3-}]$

$\dfrac{8.89 \times 10 ^{-17}}{(0.0940)^3} = [PO_4^{3-}]$

$[PO_4^{3-}] =\dfrac{8.89 \times 10 ^{-17}}{(0.0940)^3}$

$[PO_4^{3-}] =1.07 \times 10^{-13}$

The dissociation of $Ca_3(PO_4)_2$

The solubility product constant of $Ca_3(PO_4)_2$ is $2.07 \times 10^{-32}$

The dissociation of $Ca_3(PO_4)_2$ is :

$Ca_3(PO_4)_2 \to 3Ca^{2+} + 2 PO_{4}^{3-}$

Thus;

$Ksp = [Ca^{2+}]^3 [PO_4^{3-}]^2$

$2.07 \times 10^{-33} = (0.0440)^3 [PO_4^{3-}]^2$

$\dfrac{2.07 \times 10^{-33} }{(0.0440)^3}= [PO_4^{3-}]^2$

$[PO_4^{3-}]^2 = \dfrac{2.07 \times 10^{-33} }{(0.0440)^3}$

$[PO_4^{3-}]^2 = 2.43 \times 10^{-29}$

$[PO_4^{3-}] = \sqrt{2.43 \times 10^{-29}$

$[PO_4^{3-}] =4.93 \times 10^{-15}$

Thus; the phosphate anion needed for precipitation is smaller i.e $4.93 \times 10^{-15}$ in $Ca_3(PO_4)_2$ than in $Ag_3PO_4$ $1.07 \times 10^{-13}$

Therefore:

$Ca_3(PO_4)_2$ will precipitate out first

To determine the concentration of $[Ca^+]$ when the second cation starts to precipitate ; we have :

$Ksp = [Ca^{2+}]^3 [PO_4^{3-}]^2$

$2.07 \times 10^{-33} = [Ca^{2+}]^3 (1.07 \times 10^{-13})^2$

$[Ca^{2+}]^3 = \dfrac{2.07 \times 10^{-33} }{(1.07 \times 10^{-13})^2}$

$[Ca^{2+}]^3 =1.808 \times 10^{-7}$

$[Ca^{2+}] =\sqrt[3]{1.808 \times 10^{-7}}$

$[Ca^{2+}] =0.00566$

This implies that when the second cation starts to precipitate ; the concentration of $[Ca^{2+}]$ in the solution is 0.00566

Therefore;

the percentage of $Ca^{2+}$ remaining = concentration remaining/initial concentration × 100%

the percentage of $Ca^{2+}$ remaining = 0.00566/0.0440 × 100%

the percentage of $Ca^{2+}$ remaining = 0.1286 × 100%

the percentage of $Ca^{2+}$ remaining = 12.86%

5 0

3 years ago

Everything that can be measured is made up of _____ and that is made up of small units called _____?

Everything that can be measured is made up of _ and that is made up of small units called _?