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Elena L [17]
2 years ago
13

Which part of a calcium atom in the ground state is represented by the dots in its Lewis electron-dot diagram?​

Chemistry
1 answer:
g100num [7]2 years ago
8 0

Answer:

There are two dots are present on the left side of calcium atom which represents the unpaired electrons present in the outermost shell. This structure is presented by Lewis in order to show the number of unpaired electrons in the atom.

Explanation:

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What is the mass in grams of 0.000142 mol of vitamin c
bazaltina [42]

Answer:

0.0250 g

Explanation:

Step 1: Determine the molar mass of Vitamin C.

The molar mass is the mass in grams corresponding to 1 mole. In order to calculate the molar mass of vitamin C (C₆H₈O₆) we need to add the molar masses of the elements that compose it.

M(C₆H₈O₆) = 6 × M(C) + 8 × M(H) + 6 × M(O)

M(C₆H₈O₆) = 6 × 12.01 g/mol + 8 × 1.01 g/mol + 6 × 16.00 g/mol

M(C₆H₈O₆) =  176.14 g/mol

Step 2: Calculate the mass corresponding to 0.000142 mol of vitamin C.

0.000142 mol \times \frac{176.14g}{mol} =0.0250 g

7 0
3 years ago
1.5 moles of Al is how many<br> atoms?
aev [14]

Answer:

<h2>9.03 × 10²³ atoms </h2>

Explanation:

The number of atoms of Al can be found by using the formula

<h3>N = n × L</h3>

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 1.5 × 6.02 × 10²³

We have the final answer as

<h3>9.03 × 10²³ atoms</h3>

Hope this helps you

4 0
2 years ago
In a certain city, electricity costs $0.15 per kW·h. What is the annual cost for electricity to power a lamp-post for 6.00 hours
Vanyuwa [196]

(a) Power of bulb is 100 W, converting this into kW.

1 W=\frac{1}{1000}kW

Thus,

100 W =\frac{100}{1000}kW=0.1 kW

The bulb is used for 6 hours per day for a year, in 1 year there are 365 days thus, total hours will be:

t=6\times 365=2190 h

Electricity used will depend on power and number of hours as follows:

E=P\times t=0.1 kW\times 2190 h=219 kW.h

The cost of electricity is $0.15 per kW.h thus, cost of electricity for 219 kW.h will be:

Cost=\$ (219\times 0.15)=\$ 32.85

Therefore, annual cost of incandescent light bulb is \$ 32.85

(b) Power of bulb is 25 W, converting this into kW.

1 W=\frac{1}{1000}kW

Thus,

100 W =\frac{25}{1000}kW=0.025 kW

The bulb is used for 6 hours per day for a year, in 1 year there are 365 days thus, total hours will be:

t=6\times 365=2190 h

Electricity used will depend on power and number of hours as follows:

E=P\times t=0.025 kW\times 2190 h=54.75 kW.h

The cost of electricity is $0.15 per kW.h thus, cost of electricity for 54.75 kW.h will be:

Cost=\$ (54.75\times 0.15)=\$ 8.21

Therefore, annual cost of fluorescent bulb is \$ 8.21.

7 0
3 years ago
For any point on earths surface its height above sea level is called its
DedPeter [7]
Altitude, If this helped please 5 star me 
6 0
3 years ago
Read 2 more answers
Write the general chemical formula for an acid, and discuss what each component of the formula represents.
saul85 [17]
The general formula of an acid is HX where H+ acts as the cation while X can be a halogen (Cl-, Fl-, Br-, etc) and acts as the anion. There are also cases where X is an ion like SO42-, which brings two atoms of H in the formula. Strong acids dissociate completely while weak acids do not.
4 0
3 years ago
Read 2 more answers
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