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bixtya [17]
3 years ago
14

What is the gram-formula mass of Fe(NO3)3?

Chemistry
2 answers:
dusya [7]3 years ago
8 0
M Fe = 55,85g ≈ 56g
m O = 16g
m N = 14g
m Fe(NO3)3 = 56g + 3*14g + 3*3*16g = 242g/mol

answer: (4)
Inessa [10]3 years ago
6 0

Gram formula mass is the mass of 1 mol of substance.

the given compound is Fe(NO₃)₃

the molar mass of Fe(NO₃)₃ can be calculated taking the sum of the products of the individual elements by the number of atoms of the element making up the compound.

molar mass of Fe(NO₃)₃ = molar mass of Fe + 3 (molar mass of N + (3 x molar mass of O))

molar mass of Fe - 56, N - 14 and O - 16 g/mol

substituting the values in the above formula

molar mass of Fe(NO₃)₃ = 56 + 3 (14 + (3 x 16) )

molar mass of Fe(NO₃)₃ = 56 + 3 (14 + 48) = 56 + 3(62) = 56 + 186 = 242

therefore molar mass of Fe(NO₃)₃ is 4)242 g/mol

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How many grams of ammonia must you start with to make 900.00 l of a 0.140 m aqueous solution of nitric acid? assume all the reac
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<span>
1) 4NH3(g)+5O2(g)-->4NO(g)+6H2O(g)

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3) 3NO2(g)+H2O(l)-->2HNO3(aq)+NO(g)

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4 moles of NO produce 4 moles of NO2

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Calculate the number of moles of HNO3 in 900.00 l of 0.140 M solution

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Use proportions:

(</span><span>8/3) moles HNO3 / 4 moles NH3 = 126 moles HNO3 / x

=> x = 126 moles HNO3 * 4 moles NH3 / (8/3 moles HNO3) = 189 moles NH3

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Answer: 3213 g.
</span>
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