Answer:
The correct answer is option c.
Explanation:
Formula used to determine an average atomic mass :

Mass of isotope Sb-121 = 120.904 amu
Fractional abundance of Sb-121 = 57.21% = 0.5721
Mass of isotope Sb-123 = 122.904 amu
Fractional abundance of Sb-123 = 42.79% = 0.4279
Average atomic mass of Sb:

Answer:
3 element i.e carbon (C), hydrogen (H) and oxygen.
Explanation:
The following data were obtained from the question:
Subtance >>>>>>>> Chemical Formula
Glucose >>>>>>>>> C₆H₁₂O₆
Methane >>>>>>>> CH₄
Ethanol >>>>>>>>> C₂H₅OH
Hydrogen peroxide >> H₂O₂
From the above table, we can see that ethanol (C₂H₅OH) contains carbon (C), hydrogen (H) and oxygen
Therefore, the total number of elements present in ethanol, C₂H₅OH is 3.
Answer/Explanation
Characteristics of Life Present in Viruses:
- has a defined boundary - viruses are made up simply of genetic material surrounded by a<u> protein capsid </u>and sometimes a lipid membrane
Characteristics of Life Absent in Viruses:
- made up of one or more cells - one of the main arguments for why viruses are not living is that they are <u>not cellular</u>
- uses energy - this is a tricky one. They don't use or produce their own energy. However, in order to reproduce they do hijack the host cells and <u>steal energy</u> from them in order to reproduce
- exhibits growth and development - although viruses do <u>reproduce</u>, the individual viral particles do not exhibit growth or development
- possess internal organisation - other than the fact they ahve genetic material, the inside of a virus does not contain internal organization like a cytosol, instead conssiting of the bare minimum amount of proteins to survive
- eliminates waste - since they do not have their own metabolism, they have no waste to eliminate
The main function is to help them see with all their eyes.
Answer is: ph value is 3.56.
Chemical reaction 1: H₂CO₃(aq) ⇄ HCO₃⁻(aq) + H⁺(aq); Ka₁ = 4,3·10⁻⁷.
Chemical reaction 2: HCO₃⁻(aq) ⇄ CO₃²⁻(aq) + H⁺(aq); Ka₂ = 5,6·10⁻¹¹.
c(H₂CO₃) = 0,18 M.
[HCO₃⁻] = [H⁺<span>] = x.
</span>[H₂CO₃] = 0,18 M - x.
Ka₁ = [HCO₃⁻] · [H⁺] / [H₂CO₃].
4,3·10⁻⁷ = x² / (0,18 M -x).
Solve quadratic equation: x = [H⁺] =0,000293 M.
pH = -log[H⁺] = -log(0,000293 M).
pH = 3,56; second Ka do not contributes pH value a lot.