Answer:
(C) greater than zero but less than 45° above the horizontal
Explanation:
The range of a projectile is given by R = v²sin2θ/g.
For maximum range, sin2θ = 1 ⇒ 2θ = sin⁻¹(1) = 90°
2θ = 90°
θ = 90°/2 = 45°
So the maximum horizontal distance R is in the range 0 < θ < 45°, if θ is the angle above the horizontal.
Answer:
A) pitch
Explanation:
I did band and also g*ogled it to check :)
If it isn't A, however, it is C
Hope this helps :D
Hi there!
We can use the kinematic equation:
vf = Final velocity (? m/s)
vi = initial velocity (0 m/s, dropped from rest)
a = acceleration (due to gravity, 9.8 m/s²)
d = distance (9.8 m)
Simplify the equation to solve for vf:
Substitute in the given values:
Answer:
There may be excess charges in the interior of the wire
The net electric field everywhere inside the wire is zero
The interior of the metal wire is neutral.
There may be excess charges on the surface of the wire.
There is no net flow of mobile electrons inside the wire.
Explanation:
For any metal wire in equilibrium position, there may be excess charges in the interior of the wire and the net electric field everywhere inside the wire is zero. Additionally, the interior of the metal wire is always neutral and there is likely to be excess charges on the surface of the wire. Moreover, it's important to note that for a metal wire in equilibrium, there is no net flow of mobile electrons inside the wire.
Answer:
1) MANTLE 2) MAGMA 3) MINERALS
Explanation:
I just did the assignment and got it correct hope this helps
