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nignag [31]
3 years ago
15

Which of the following is an example of a physical change? burning paper digesting food o ripping paper​

Physics
1 answer:
tekilochka [14]3 years ago
4 0
Ripping paper, because you are changing the physical appearance. The other answer choices are an example of chemical change.
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A woman living in a third-story apartment is moving out. Rather than carrying everything down the stairs, she decides to pack he
Flura [38]

Answer:

T = 480.2N

Explanation:

In order to find the required force, you take into account that the sum of forces must be equal to zero if the object has a constant speed.

The forces on the boxes are:

T-Mg=0      (1)

T: tension of the rope

M: mass of the boxes 0= 49kg

g: gravitational acceleration = 9.8m/s^2

The pulley is frictionless, then, you can assume that the tension of the rope T, is equal to the force that the woman makes.

By using the equation (1) you obtain:

T=Mg=(49kg)(9.8m/s^2)=480.2N

The woman needs to pull the rope at 480.2N

8 0
3 years ago
What is the source of waves​
Wittaler [7]

Answer:

the ocean

Explanation:

the ocean I think

7 0
3 years ago
Read 2 more answers
A proton moves through a magnetic field at 20.3 % of the speed of light. At a location where the field has a magnitude of 0.0062
galina1969 [7]

Answer:

Force on the proton will be .73\times 10^{-14}N

Explanation:

We have given speed of proton is 20.3% of speed of light

Speed of light c=3\times 10^8m/sec

So speed of proton v=\frac{3\times 10^8\times 23}{100}=6.9\times 10^7m/sec

Magnetic field B = 0.00629 T

Charge on proton q=1.6\times 10^{-16}C

Angle between velocity and magnetic field \Theta =137^{\circ}

Force on the proton is equal to F=qvBsin\Theta =1.6\times 10^{-19}\times 6.9\times 10^7\times 0.00629\times sin(137^{\circ})=4.73\times 10^{-14}N

4 0
3 years ago
A 6.0 kg bowling ball moving at 3.5m/s to the right makes a collision, head-on, with a stationary 0.70 kg bowling pin. If the ba
devlian [24]

Answer:

The velocity of the pin will be 6.26 m/s in the right direction.

Explanation:

Let's use the momentum conservation equation.

p_{i}=p_{f}

Initially, we have:

p_{i}=m_{b}*v_{ib}

Where:

  • m(b) is the ball mass
  • v(ib) is the initial velocity of the ball

Now, the final momentum will be:

p_{f}=m_{b}*v_{fb}+m_{p}*v_{fp}

Where:

  • m(p) is the pin mass
  • v(fb) is the final velocity of the ball
  • v(fp) is the final velocity of the pin

Then, using the equation of the conservation we have:

m_{b}*v_{ib}=m_{b}*v_{fb}+m_{p}*v_{fp}

6*3.5=6*2.77+0.7*v_{fp}

6*3.5=6*2.77+0.7*v_{fp}

v_{fp}=6.26 m/s

Therefore the velocity of the pin will be 6.26 m/s in the right direction.

I hope it helps you!

4 0
3 years ago
The ejection seat has an acceleration of 8gees (8xgravity or ~80m/s/s). He has a mass of 70kg. The total force on him from the c
Georgia [21]

I assume you're talking about a pilot. If the ejection seat has an acceleration of 8<em>g</em>, then it would exert a normal force of 8<em>g</em> (70 kg) ≈ 5600 N.

(This is assuming the pilot is flying horizontally at a constant speed, and the seat is ejected vertically upward.)

To reiterate, this is *only* the force exerted by the seat on the pilot. Contrast this with the <em>net</em> force on the pilot, which would be the normal force minus the pilot's weight, 5600 N - (70 kg)<em>g</em> ≈ 4900 N.

If instead the seat ejects the pilot directly downward, the force exerted by the seat would have the same magnitude of 5600 N, but its direction would be reversed to point downward, making it negative. But the <em>net</em> force would change to -5600 N - (70 kg)<em>g</em> ≈ -6300 N

5 0
3 years ago
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