If a student took seven science classes, his/her at score would be 1200.
<h3>What is a graph?</h3>
A graph is a relationship in which data is presented on the axes of cartesian coordinates. The presentation of the graph must be such that it is easy to read off the graph.
Now we can see that the graph is a plot of SAT scores versus the number of science classes that students take. In this case, the slope would tell us the score per subject of a student in the SAT.
a) The mathematical model that re[resents this graph is;
y =100x + 500
b) The slope of the graph must be obtained by the use of two points thus;
m = y2 - y1/x2 - x1
m = 600 - 500/1 - 0
m = 100
c) Using the relation;
y = mx + c
m = 100
c = 500
y = 100(7) + 500
y = 1200
Thus if a student took seven science classes, his/her at score would be 1200.
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The car at 60 kph has 9 times more kinetic energy than the car traveling at 20 kph. This assumes that both cars have the same mass. Kinetic energy depends on the square of thee speed so if one car is going 3 times faster, its kinetic energy will be 3^2 ( = 9 ) greater. The car going at 60 kph will have 4 times the KE of the car going at 30 kph ( again assuming that the cars have the same mass.)
<h3>Answer;</h3>
<u>It would make the lens stronger. </u>
<h3>Explanation;</h3>
- The focal length is the distance between the optical center or the center of the lens to the focal point of a convex or concave lens.
- The power of the convex lens is lens ability to undertake refraction or bend light. It is given as the reciprocal of focal length.
- Power of the lens = 1/ f; therefore the smaller the focal length the higher the power and the larger the focal length the lower the power.
- Thus; decreasing the focal length of a convex lens makes the lens stronger.
Answer:
You would hear a loud trumpet sound that can be heard from a large distance.
Explanation:
Q before connected = Q after connected C1V1+C2V2 = (C1+C2) V
C1= 3×10^-6 F
V1= 480v
C2= 4×10^-6 F
V2= 500v
(3×10^-6)×(480) + (4×10^-6)×(500) = (3×10^-6 + 4×10^-6) × V
Simplifying the above, we get:
( 1440× 10^-6) + (2000 ×10^-6) = (7 × 10^-6) × V.
Further simplified as:
3440 × 10^-6 = 7 × 10^-6 × V
Making V the subject
V = 491.43volts
Therefore the potential difference across each capacitor is 491.43v