Answer:
Kc=13.61
Explanation:
A chemical equilibrium is the situation in which the ratio between the amounts of reagents and products in a chemical reaction remains constant over time.
The equilibrium constant (Kc) is useful for the study of chemical equilibrium, being a constant that indicates whether the reaction is favored to the formation of products or to the formation of reactants.
Being:
aA + bB ⇔ cC + dD
where a, b, c, d are the stoichiometric coefficients of the reaction and A, B, C, D are the symbols or formulas of the different substances involved
Then:
![Kc=\frac{[C]^{c} *[D]^{d} }{[A]^{a} *[B]^{b} }](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BC%5D%5E%7Bc%7D%20%2A%5BD%5D%5E%7Bd%7D%20%7D%7B%5BA%5D%5E%7Ba%7D%20%2A%5BB%5D%5E%7Bb%7D%20%7D)
where [] is the Molar concentration of each of the substances in equilibrium.
In this case, you know: 2 SO₂(g) +O₂(g)⇌2 SO₃(g)
So: ![Kc=\frac{[SO_{3} ]^{2} }{[SO_{2}] ^{2} *[O_{2} ]}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BSO_%7B3%7D%20%5D%5E%7B2%7D%20%7D%7B%5BSO_%7B2%7D%5D%20%5E%7B2%7D%20%2A%5BO_%7B2%7D%20%5D%7D)
Being: [SO2]=0.48 M, [O2]=0.40 M, and [SO3]=1.12 M
![Kc=\frac{[1.12]^{2} }{[0.48] ^{2} *[0.40 ]}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5B1.12%5D%5E%7B2%7D%20%7D%7B%5B0.48%5D%20%5E%7B2%7D%20%2A%5B0.40%20%5D%7D)
Kc=13.61
The chemical reaction would be:
C3H8 + 5O2 = 3CO2 + 4H2O
For this case, we assume that gas is ideal thus in every 1 mol the volume would be 22.41 L. We calculate as follows:
28.7 L C3H8 ( 1 mol / 22.41 L ) ( 4 mol H2O / 1 mol C3H8 ) ( 18.02 g / mol ) = 92.31 g H2O produced
Hope this answers the question.