Electronic configuration: The distribution or arrangement of electrons of a molecule or an atom in molecular or atomic orbitals.
Ground state electron configuration: The distribution of electrons of an atom or molecule around the nucleus with lower levels of energy.
Now, 
stands for Ruthenium with atomic number 44. It is a metal and thus, has ability to lose electrons and, becomes positively charged ion.
One can write the electronic configuration with the help of atomic number and Afbau principle, Pauli exclusion principle etc.
Ground electronic Configuration is as follows:
Soft Hand notation: ![[Kr]4d^{7}5s^{1}](https://tex.z-dn.net/?f=%5BKr%5D4d%5E%7B7%7D5s%5E%7B1%7D)
Now, when ruthenium loses two electrons then it becomes 
, thus electron configuration becomes
Soft Hand notation: ![[Kr]4d^{6}](https://tex.z-dn.net/?f=%5BKr%5D4d%5E%7B6%7D)
The ground state electronic configuration of Ruthenium is and when it loses two electrons, then electronic configuration becomes ( )
Two astronauts would exhale about 40 moles of carbon dioxide daily.
Carbon dioxide reacts with lithium hydroxide in a 1 : 2 mole ratio. Set up a proportion:
1 : 2 = 40 : x
Then, find x:
<span>12=40x
</span>
Cross multiply. x = 80 moles of LiOH per day for both astronauts
C. "A" mentions that the drug killed all of the bacteria that are resistant to the drug, and that doesn't make any sense. "B" claims that all bacteria are resistant to the drug. This is not true. "D" mentions that bacteria eat the drug, which doesn't happen.
I thinking the limitation is that a shifting electron will always move from a more excited states to a less excited state. Electrons could not circle the nucleus because they would lose energy by emitting electromagnetic radiation and spiral into the nucleus. In addition Bohr was not able to explain electrons orbits of large atom w/many electrons.
Answer:
CH4
Explanation:
The number of moles of carbon and hydrogen has been given as follows:
C = 0.300 mol
H = 1.20 mol
Next, we divide each mole value by the smallest (0.300)
C = 0.300 ÷ 0.300 = 1
H = 1.20 ÷ 0.300 = 4
The empirical ratio of Carbon and Hydrogen is 1:4, hence, the empirical formula is CH4
