3 years ago

28 points

Physics

1 answer:

dem82 [27]3 years ago

7 0

Answer: C. 1.64 x 10-3 m/s2

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a 2.0-mole sample of an ideal gas is gently heated at constant temperature 330 k. it expands from initial volume 19 l to final v

shutvik [7]

Isothermal Work = PVln(v₂/v₁)

PV = nRT = 2 mole * 8.314 J/ (k.mol) * 330 k = 5487.24 J

Isothermal Work = PVln(v₂/v₁) v₂ = ? v₁ = 19L,

1.7 kJ = (5487.24)In(v₂/19)

1700 = (5487.24)In(v₂/19)

In(v₂/19) = (1700/5487.24) = 0.3098

In(v₂/19) = 0.3098

(v₂/19) = $e^{0.3098}$

v₂ = 19* $e^{0.3098}$

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v₂ ≈ 26 L Option b.

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Which example has the least kinetic energy

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Answer:

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Let’s calculate the kinetic energy for all of the choices.

a. (1/2)(100)(100)^2 = 50(10000)=500,000

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We can see that (d) has the least kinetic energy.

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For the dry and static friction materials, some of these are Rubber, Aluminum, Gold, Platinum,

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