1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sauron [17]
3 years ago
7

Is it possible to have a charge of 5 x 10-20 C? Why?

Physics
1 answer:
ruslelena [56]3 years ago
8 0

1) No

2) Yes

3) No

4) Equal and opposite

5) 32400 N

6) Repulsive

7) The electric force is 2.3\cdot 10^{39} times bigger than the gravitational force

Explanation:

1)

In nature, the minimum possible charge that an object can have is the charge of the electron, which is called fundamental charge:

e=1.6\cdot 10^{-19}C

Electrons are indivisible particles (they cannot be separated), this means that an object can have at least the charge equal to the charge of one electron (in fact, it cannot have a charge less than e, because it would meant that the object has a "fractional number" of electrons).

In this problem, the object has a charge of

Q=5\cdot 10^{-20}C

If we compare this value to e, we notice that Q, so no object can have a charge of Q.

2)

As we said in part 1), an object should have an integer number of electrons in order to be charged.

This means that the charge of an object must be an integer multiple of the fundamental charge, so we can write it as:

Q=ne

where

Q is the charge of the object

n is an integer multiple

e is the fundamental charge

Here we have

Q=2.4\cdot 10^{-18}C

Substituting the value of e, we find n:

n=\frac{Q}{e}=\frac{2.4\cdot 10^{-18}}{1.6\cdot 10^{-19}}=15

n is integer, so this value of the charge is possible.

3)

We now do the same procedure for the new object in this part, which has a charge of

Q=2.0\cdot 10^{-19}C

Again, the charge on this object can be written as

Q=ne

where

n is the number of electrons in the object

Using the value of the fundamental charge,

e=1.6\cdot 10^{-19}C

We find:

n=\frac{Q}{e}=\frac{2.0\cdot 10^{-19}}{1.6\cdot 10^{-19}}=1.25

n is not integer, so this value of charge is not possible, since an object cannot have a fractional number of electrons.

4)

To solve this part, we use Newton's third law of motion, which states that:

"When an object A exerts a force on an object B (Action force), then object B exerts an equal and opposite force on object A (reaction force)".

In this problem, we have two objects:

- A charge Q

- A charge 5Q

Charge Q exerts an electric force on charge 5Q, and we can call this action force. At the same time, charge 5Q exerts an electric force on charge Q (reaction force), and according to Newton's 3rd law, the two forces are equal and opposite.

5)

The magnitude of the electric force between two single-point charges is

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the two charges

r is the separation between the two charges

In this problem we have:

q_1=+4.5\cdot 10^{-6}C is charge 1

q_2=+7.2\cdot 10^{-6}C is charge 2

r = 0.30 cm = 0.003 m is the separation

So, the electric force  between the two charges is

F=(9\cdot 10^9)\frac{(4.5\cdot 10^{-6})(7.2\cdot 10^{-6})}{(0.003)^2}=32400 N

6)

The electric force between two charged objects has direction as follows:

- If the two objects have charges of opposite signs (+ and -), the force between them is attractive

- If the two objects have charges of same sign (++ or --), the force between them is repulsive

In this problem, the two charges are:

q_1=+4.5\cdot 10^{-6}C is charge 1

q_2=+7.2\cdot 10^{-6}C is charge 2

We see that the two charges have same sign: therefore, the force between them is repulsive.

7)

The electric force between the proton and the electron in the atom can be written as

F_E=k\frac{q_1 q_2}{r^2}

where

q_1 = q_2 = e = 1.6\cdot 10^{-19}C is the magnitude of the charge of the proton and of the electron

r=5.3\cdot 10^{-11} m is the separation between them

So the force can be rewritten as

F_E=\frac{ke^2}{r^2}

The gravitational force between the proton and the electron can be written as

F_G=G\frac{m_p m_e}{r^2}

where

G is the gravitational constant

m_p = 1.67\cdot 10^{-27}kg is the proton mass

m_e=9.11\cdot 10^{-27}kg is the electron mass

Comparing the 2 forces,

\frac{F_E}{F_G}=\frac{ke^2}{Gm_p m_e}=\frac{(9\cdot 10^9)(1.6\cdot 10^{-19})^2}{(6.67\cdot 10^{-11})(1.67\cdot 10^{-27})(9.11\cdot 10^{-31})}=2.3\cdot 10^{39}

You might be interested in
Which is true of oxidation? PLS HELP FAST and thank you!
elena-14-01-66 [18.8K]

Answer:The Answer Is D

Explanation:

4 0
2 years ago
What are four types of pathogens and what type of disease or sickness do they cause?
Zanzabum

Bacteria( cholera)

Virus( AIDS)

Fungi(athlete's foot)

Protist( malaria)

Pleasssssssse mark me as brainliest

7 0
3 years ago
why does diving 30m below sea level affect our bodies more than being in a building 30m above sea level
Genrish500 [490]
Imagine you are in a swimming pool 30m deep. Assuming you know that water is denser than air, you would know that the 30m of water above you will carry more weight, and press down on your body. Say you were in a swimming pool 60m deep, you would be sandwiched between 30m of water pressing down on you, and the upthrust created by the 30m of water below you.

In a building 30m up, the pressure will be regulated, as you are in a building. The floor will be strong enough to support the weight of the body, and the body will not recoil into itself.
5 0
2 years ago
Which of the following statements explains one way that oceans influence the temperature of the tropics and poles?
pogonyaev

Answer:

c

Explanation:

5 0
2 years ago
base your answer to this question on the information below and on your knowledge of physics. A toy launcher that is used to laun
Nadya [2.5K]

Answer: v = 2.24 m/s

Explanation: The <u>Law</u> <u>of</u> <u>Conservation</u> <u>of</u> <u>Energy</u> states that total energy is constant in any process and, it cannot be created nor destroyed, only transformed.

So, in the toy launcher, the energy of the compressed spring, called <u>Elastic</u> <u>Potential</u> <u>Energy (PE)</u>, transforms into the movement of the plastic sphere, called <u>Kinetic</u> <u>Energy (KE)</u>. Since total energy must be constant:

KE_{i}+PE_{i}=KE_{f}+PE_{f}

where the terms with subscript i are related to the initial of the process and the terms with subscript f relates to the final process.

The equation is calculated as:

\frac{1}{2}kx^{2}+0=0+\frac{1}{2}mv^{2}

\frac{1}{2}kx^{2}=\frac{1}{2}mv^{2}

\frac{1}{2}50(0.1)^{2}=\frac{1}{2}(0.1)v^{2}

v^{2}=\frac{50(0.1)^{2}}{0.1}

v=\sqrt{50(0.1)}

v=\sqrt{5}

v = 2.24

The maximum speed the plastic sphere will be launched is 2.24 m/s.

3 0
3 years ago
Other questions:
  • : Two containers have a substantial amount of the air evacuated out of them so that the pressure inside is half the pressure at
    10·1 answer
  • Scientific theories cannot change once they've been written down true or false ​
    15·2 answers
  • . Point charges q1 = q2 = 4.0 × 10−6 C are fixed on the x-axis at x = −3.0 m and x = 3.0 m. What charge q must be placed at the
    6·1 answer
  • Bodies A and B have equal mass. Body B is initially at rest. Body A collides with body B in a one–dimensional elastic collision.
    8·2 answers
  • A recent study found that electrons that have energies between 3.45 eV and 19.9 eV can cause breaks in a DNA molecule even thoug
    6·1 answer
  • Helloooooooooooo<br><br><br> A) HI<br><br> B) GO AWAY<br><br> C) BYE FELICIA<br><br> D) HELLO MATE
    13·1 answer
  • a boy runs from his house to school at speed 5m/s on a straight road and returns with speed of 10m/s.The distance between the ho
    8·1 answer
  • How much work is done using a 500 W microwave for 5 minutes
    7·1 answer
  • How much current would flow in a device powered by four 1.5 V batteries through a bulb that had a resistance of 51.0 ohms?
    8·1 answer
  • Fish are hung on a spring scale to determine their mass (most fishermen feel no obligation to report the mass truthfully). (a) W
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!