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boyakko [2]
3 years ago
11

Solve for b. 4/3b+2=4-1/3b​

Mathematics
1 answer:
Maksim231197 [3]3 years ago
4 0

Answer:

b = \frac{6}{5}

Step-by-step explanation:

Multiply through by 3 to clear the fractions.

4b + 6 = 12 - b ( add b to both sides )

5b + 6 = 12 ( subtract 6 from both sides )

5b = 6 ( divide both sides by 5 )

b = \frac{6}{5}

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A spinner is broken into section labeled 1 to 38. What is the probability that.On your next spin, that you will spin a 1?
VashaNatasha [74]

Answer:

1/38

Step-by-step explanation:

Given :

Probability = required outcome / Total possible outcomes

Total possible outcomes = total Numbe rod sections = 38

Required outcome = number of 1's on the entire section = 1

Hence, the probability of spinning a one equals :

P(spinning a 1) = 1 / 38

8 0
3 years ago
Please help! what is the polar equation r = -5 theta in parametric form?<br><br> thank you!
Rudiy27

Use these equations when converting polar equations to parametric equations:

x=r\cos\theta

y=r\sin\theta

We know that r=5\theta, so substitute that into both equations for x and y.

x=5\theta\cos\theta

y=5\theta\sin\theta

Now, replace \theta with any variable that you want to represent the parametric equations in. I'll use the standard variable, t

x=5t\cos t

y=5t\sin t

Thus, r=5\theta represented in parametric form is:

(x,y)=(5t\cos t, 5t \sin t)

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~ Padoru

4 0
3 years ago
(4m-2) (m2 + 5m - 6)please fast​
Masteriza [31]

Answer:

4m3+18m2−34m+12

Step-by-step explanation:

=(4m+−2)(m2+5m+−6)

=(4m)(m2)+(4m)(5m)+(4m)(−6)+(−2)(m2)+(−2)(5m)+(−2)(−6)

=4m3+20m2−24m−2m2−10m+12

3 0
3 years ago
Read 2 more answers
Help me with this question plz
Alik [6]

Answer:

i dont what it could be but my uncle said it was 32 but i dont know if its correct

Step-by-step explanation:

8 0
3 years ago
Find the volumes of the solids generated by revolving the triangle with vertices (2, 2)​, (2, 6)​, and (5, 6) about ​a) the​ x-a
Vesna [10]
  • About the x-axis (washer method):

\displaystyle\pi\int_2^5\left(6^2-\left(\frac43x-\frac23\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(20+x-x^2)\,\mathrm dx=\boxed{56\pi}

  • About the y-axis (shell method):

\displaystyle2\pi\int_2^5x\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5x(5-x)\,\mathrm dx=\boxed{36\pi}

  • About x=7 (shell method):

\displaystyle2\pi\int_2^5(7-x)\left(6-\left(\frac43x-\frac23\right)\right)\,\mathrm dx=\frac{8\pi}3\int_2^5(35-12x+x^2)\,\mathrm dx=\boxed{48\pi}

  • About y=2 (washer method):

\displaystyle\pi\int_2^5\left((6-2)^2-\left(\frac43x-\frac23-2\right)^2\right)\,\mathrm dx=\frac{16\pi}9\int_2^5(5+4x-x^2)\,\mathrm dx=\boxed{32\pi}

7 0
4 years ago
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