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2 years ago

A pendulum consisting of a sphere suspended from a light string is oscillating with a small angle with respect to

Physics

1 answer:

Jobisdone [24]2 years ago

7 0

Answer:

Explanation:

The time period of a simple pendulum: It is defined as the time taken by the pendulum to finish one full oscillation and is denoted by “T”.

The period of simple pendulum is given as

T=2π√l/g

Increasing the density of the object implies that the mass has increased

Because density is mass/volume

The period is independent on the density of the object, it depends on the length of the string and the acceleration due to gravity. So the period remains the same.

2. Acceleration

The acceleration of a simple pendulum is given as

a=-gSin θ

Therefore the acceleration is independent on the density of the object, it depends on the acceleration due to gravity and the angle of displacement.

Then, the acceleration remains the same.

So the answer is Option C,

Same

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2 years ago

Read 2 more answers

A 36.0 kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 130

konstantin123 [22]

Answer:

(a) W = 650J

(b) Wf = 529.2J

(d) W = 0J

(e) ΔK = 120.8J

(f) v2 = 2.58 m/s

Explanation:

(a) In order to find the work done by the applied force you use the following formula:

$W=Fd$ (1)

F: applied force = 130N

d: distance = 5.0m

$W=(130N)(5.0m)=650J$

The work done by the applied force is 650J

(b) The increase in the internal energy of the box-floor system is given by the work done of the friction force, which is calculated as follow:

$W_f=F_fd=\mu Mgd$ (2)

μ: coefficient of friction = 0.300

M: mass of the box = 36.0kg

g: gravitational constant = 9.8 m/s^2

$W_f=(0.300)(36.0kg)(9.8m/s^2)(5.0m)=529.2J$

The increase in the internal energy is 529.2J

(c) The normal force does not make work on the box because the normal force is perpendicular to the motion of the box.

$W = 0J$

(d) The same for the work done by the normal force. The work done by the gravitational force is zero because the motion of the box is perpendicular o the direction of the gravitational force.

(e) The change in the kinetic energy is given by the net work on the box. You use the following formula:

$\Delta K=W_T$ (3)