1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
liraira [26]
3 years ago
14

In 1986, several robotic spacecrafts were sent into space to study the Halley's Comet. Which of these statements best explains w

hy humans should continue to send robotic spacecrafts into space?
a. They absorb harmful radiations in space.
b. They help change weather conditions on Earth.
c. They help discard some myths about objects in space.
d. They destroy meteors and comets which might strike Earth.
Physics
1 answer:
Archy [21]3 years ago
8 0
<span>c. They help discard some myths about objects in space.

When we learn something new, then we know more stuff,
and that helps us avoid ignorance and superstition.

The REAL question is:  
</span><span>Why should we continue to send robotic spacecrafts,
and NOT spacecrafts piloted by people ?</span>
You might be interested in
A hiker throws a ball at an angle of 21.0° above the horizontal from a hill 21.0 m high. The hiker’s height is 1.750 m. The magn
nydimaria [60]

Answer:

38.8 m

Explanation:

h = -(21 + 1.75) = - 22.75 m

g = - 9.8 m /s^2

Ux = 14.004 m/s

Uy = + 5.376 m/s

Let the ball hits the ground in time t and at a distance d from the base of hill.

Use second equation of motion

h = Uyt + 0.5 at^2

- 22.75 = 5.376 t - 0.5 x 9.8 t^2

4.9 t^2 - 5.376 t - 22.75 = 0

t=\frac{5.376\pm \sqrt{5.376^{2}+4\times 4.9\times 22.75}}{9.8}

By solving

t = 2.77 second

So, horizontal distance

d = Ux t

d = 14.004 x 2.77 = 38.8 m

6 0
3 years ago
Which list of factors best supports the concept that they are "just right" for the planet earth to support life?
Ivanshal [37]
Temperature, gravity, atmosphere and water
8 0
3 years ago
Read 2 more answers
An electron is released from rest at the negative plate of a parallel-plate capacitor. If the distance across the plate is 2.0 m
ddd [48]

Answer:

Velocity of electron will be 1.325\times 10^6m/sec

Explanation:

We have given distance across the plate d = 2 mm =2\times 10^{-3}m

Potential difference V = 6 volt

We know that potential difference at any distance is given by

V = Ed , here V is potential difference, E is electric field and d  is distance

So E=\frac{V}{d}=\frac{6}{2\times 10^{-3}}=3000N/C

Charge on electron e=1.6\times 10^{-19}C

We know that expression of velocity is given by v=\sqrt{\frac{2qEd}{m_e}}, here q is charge on electron, E is electric field and d is distance

So v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 3000\times 3000}{9.11\times 10^{-31}}}=1.325\times 10^6m/sec

8 0
4 years ago
Which one is series and which one is parallel ( i give 20 points who answer )
slega [8]

Answer:

figure (a) L1 is series and L2 is parallel to L3

figure (b) L2 and L3 are parallel to L1

4 0
2 years ago
You attach a meter stick to an oak tree, such that the top of the meter stick is 2.07 meters above the ground. Later, an acorn f
ra1l [238]

Answer:

5.05 m

Explanation:

length of stick (L) = 1 m

distance from the top of the stick to the ground (d) = 2.07 m

time taken for corn to travel the length of the stick (t) = 0.121 s

acceleration due to gravity (a) = 9.8 m/s^{2}

we can get the distance in four stages.

  • Finding the velocity the corn was moving at from s=vt+0.5at^{2}

       where s = length of stick, t = time, a = acceleration due to gravity

       s=vt+0.5at^{2}

       1 = 0.121u + (0.5 x 9.8 x 0.121 x 0.121)

       1 = 0.121v +  0.0717

       1 - 0.0717 = 0.121v

       v = 7.67 m/s

  • Using the velocity above to find the time it took for the corn to fall to the top of the stick from the formula v = u + at' where:

       v = final velocity = 7.67 m/s

       u = initial velocity = 0 m/s since it was initially at rest

       a = acceleration due to gravity

       t' = time taken to fall to the top of the stick

        7.67 = 0 + (9.8 x t')

        t' = 7.67 / 9.8 = 0.78 s

  • using the time above to find the distance between the branch the corn falls from and the top of the stick using s=vt+0.5at^{2} where:

        s = distance

        v = initial velocity = 0 m/s since it was initially at rest

        t = time = 0.78 s

        a = acceleration due to gravity = 9.8

        s = 0 + (0.5 x 9.8 x 0.78 x 0.78)

        s = 2.98 m

  • Add the distance between the branch the corn falls from and the top of the stick and the distance from the top of the stick to the ground.

        2.98 + 2.07 = 5.05 m

       

5 0
3 years ago
Other questions:
  • In a chemical equation, the chemicals that react are considered . In a chemical equation, the chemicals that are produced are co
    15·2 answers
  • A horizontal steel bar of uniform mass density and mass 5kg is supported by two vertical steel cables atteached to the ends of t
    8·1 answer
  • A large box of mass M is moving on a horizontal floor at speed v0. A small box of mass m is sitting on top of the large box. The
    12·1 answer
  • A spring has an unstretched length of 14 cm . When an 81 g ball is hung from it, the length increases by 6.0 cm . Then the ball
    15·1 answer
  • What is the si unit amperes used to measure??
    14·1 answer
  • a cell supplies a current 0.9A through a resistance of 2 ohms and a current of 0.3A through a resistance of 7 ohms. what is inte
    11·1 answer
  • The molecule arrangement of ice, water and steam are very different. _______ has the most ordered arrangement, ______ has the ne
    5·1 answer
  • You measured the voltage across the battery terminals both for the circuit connected to the battery and for no circuit connected
    11·1 answer
  • A certain organ pipe, open at both ends, produces a fundamental frequency of 288 Hz in air. Part A If the pipe is filled with he
    8·1 answer
  • An object moves from point A to point B to point C, then back to point B and then to point C along the line
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!