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liraira [26]
3 years ago
14

In 1986, several robotic spacecrafts were sent into space to study the Halley's Comet. Which of these statements best explains w

hy humans should continue to send robotic spacecrafts into space?
a. They absorb harmful radiations in space.
b. They help change weather conditions on Earth.
c. They help discard some myths about objects in space.
d. They destroy meteors and comets which might strike Earth.
Physics
1 answer:
Archy [21]3 years ago
8 0
<span>c. They help discard some myths about objects in space.

When we learn something new, then we know more stuff,
and that helps us avoid ignorance and superstition.

The REAL question is:  
</span><span>Why should we continue to send robotic spacecrafts,
and NOT spacecrafts piloted by people ?</span>
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HELP HELP HELP ME!!!
zzz [600]
I believe the answer is C. Hope this helps!!

7 0
3 years ago
Which career is most concerned with the study of radioactive isotopes?
leonid [27]
<span>The career that is most concerned with the study of radioactive isotopes is chemistry. You need to have passed AP chemistry to actually deal with the isotopes. In a quick reference, isotopes are when the atom has difference amount of neutrons, making the atomic mass differ.</span>
3 0
3 years ago
Q.Solve the following circuit find total resistance RT. Also find value of voltage across resister RC.
vagabundo [1.1K]

Answer:

R_total = 14.57 Ω ,  V_C = 1.176 V

Explanation:

To solve this circuit we are going to find the equivalent resistance of each branch, let's remember

* Serial resistance  

         R_{eq} = ∑ R_{i}

* For resistance in parallel

        1 / R_{eq} = ∑ 1/R_{i}

We solve the two branches of the wheatstone bridge

Series resistors

Branch B

         R_B = Rb + R4

         R_B = 2 + 18

         R_B = 20 Ω

Branch C

         R_C5 = Rc + R5

         R_C5 = 3 + 12

         R_C5 = 15 Ω

Resistance in parallel R_B and R_C5

         1 / R_BC = 1 / R_B + 1 / R_C5

          1 / R_BC = 1/20 + 1/15 = 0.116666

          R_BC = 8.57 Ω

Now we have a single branch, we solve the series resistance

          R_total = R_A + R_BC

          R_total = 6 + 8.57

          R_total = 14.57 Ω

b) they ask us for the voltage in the resistance R_C

Let's remember that the voltage in a series circuit is the sum of the voltages

           10 = V_a + V_BC

           10 = i R_a + i R_BC = i (R_a + R_BC)

           i = 10 / (R_a + R_BC)

           i = 10 / (14.57)

           i = 0.6863 A

The current in the series circuit is constant

          V_BC = i R_BC

          V_BC = 0.6863 8.57

          V_BC = 5.8819 V

This voltage is divided in the bridge, for the two branches in parallel it is the same, but the resistance is different in each branch.

     Branch C

             V_BC = i R_C5

             i = V_BC / R_C5

             i = 5.8819 / 15

             i = 0.39213 A

In this branch we have two resistors in series, let's remember that the current in a series circuit is constant

             V_C = i R_C

              V_C = 0.39213 3

              V_C = 1.176 V

3 0
3 years ago
A helium nucleus is composed of two protons (positively charged) and two neutrons (charge neutral). The distance between the two
lora16 [44]

Answer:

Using the given values

F = K q^2 / r^2 = 9 * 10E9 * (1.6 * E-19)^2 / (5.18 * E-15)^2 N

E = 9 * 1.6^2 / 5.18^2 * 10 = 8.5 N

5 0
2 years ago
Which of the following devices is associated with the reception of radio signals?
ki77a [65]
What are the "following" devices ? ?
I think they're a list of choices that you have but aren't sharing.

A few devices associated with the reception of various types of
radio signals include the resonant tank, the local oscillator, the
mixer, the detector, the coherer, the discriminator, the parabolic
reflector, the lecher wires, the audio transducer, the demultiplexer,
and ... my personal guess ... the 'antenna' or 'aerial'.
6 0
2 years ago
Read 2 more answers
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