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lord [1]
3 years ago
7

Calculate the gravitational force between a 10 kg ball and 20 kg ball

Physics
1 answer:
elena-s [515]3 years ago
7 0

Answer:

5.34\cdot 10^{-10} N

Explanation:

The gravitational force is an attractive force exerted between any objects with mass.

The magnitude of the gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the masses of the two objects

r is the separation between the two objects

In this problem, we have:

m_1 = 10 kg is the mass of the 1st ball

m_2 = 20 kg is the mass of the 2nd ball

r = 5 m is the separation

So, the gravitational force between them is

F=(6.67\cdot 10^{-11})\frac{(10)(20)}{5^2}=5.34\cdot 10^{-10} N

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5 0
4 years ago
Read 2 more answers
Two vectors are given by a = 8.6i + 5.1 j and b = 931 + 9.5.
skelet666 [1.2K]

Answer:

<u>Assuming b = 9.3i + 9.5j</u> <em>(b = 931 + 9.5 is wrong):</em>

a) a×b = 34.27k

b) a·b = 128.43

c) (a + b)·b = 305.17

d) The component of a along the direction of b = 9.66

Explanation:

<u>Assuming b = 9.3i + 9.5j</u> <em>(b = 931 + 9.5 is wrong)</em> we can proceed as follows:  

a) The vectorial product, a×b  is:

a \times b = (8.6*9.5 - 5.1*9.3)k = 34.27k

b) The escalar product a·b is:

a\cdot b = (8.6*9.3) + (5.1*9.5) = 128.43

c) <u>Asumming (a</u><u> </u><u>+ b)·b</u> <em>instead a+b·b</em> we have:

(a + b)\cdot b = [(8.6 + 9.3)i + (5.1 + 9.5)j]\cdot (9.3i + 9.5j) = (17.9i + 14.6j)\cdot (9.3i + 9.5j) = 305.17

d) The component of a along the direction of b is:

a*cos(\theta) = \frac{a\cdot b}{|b|} = \frac{128.43}{\sqrt{9.3^{2} + 9.5^{2}}} = 9.66

I hope it helps you!                        

5 0
4 years ago
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