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Novay_Z [31]
3 years ago
12

What is a dependent variable

Physics
2 answers:
kramer3 years ago
8 0

Answer:

the variable you change in a experiment

Explanation:

a variable (often denoted by y ) whose value depends on that of another.

Len [333]3 years ago
6 0
A variable (often denoted by y ) whose value depends on that of another.
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For each of the statements below, decide which of the Maxwell equations (forstaticsituations) tells you that the statement is tr
Vladimir79 [104]

Answer:

(a)There are no magnetic monopoles. true

(c) There must be a vector potential. true

(d) Charges create electric fields.2. true

Explanation:

a) there are no magnetic monopoles because magnetic field is created by charges (electrons) and these electrons have dipole field so it is not possible to have magnetic dipoles, more ever Gauss's law always explained that there are not magnetic dipoles. furthermore magnetic monopoles aree caused by magnetic charges and we have electric charges.

c)vector potential is a vector field which serves as a potential for magnetic field so, the magnetic field B by Faraday and Gauss's law is also known as vector potential.

d) electric field is solely generated by charges be it static charges or moving charges if there are no charges it is not possible to have an electric field.

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3 years ago
What must the driver do when approaching an intersection and seeing the traffic light turn from green to yellow?
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The person should start to slow down but if close enough or in the intersection go threw. Otherwise come to a complete stop until the light turns green again
4 0
3 years ago
A boy is exerting a force of 70 N at a 50-degree angle on a lawn mower. He is accelerating at 1.8 m/s2. Round the answers to the
charle [14.2K]

Answer:

are you in middle school

Explanation:

need more evendice

8 0
3 years ago
A quarterback throws a football 40 yards in 4 seconds.what is the average speed the football
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8 0
3 years ago
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A convex lens has a focal length of 16.5 cm. Where on the lens axis should an object be placed in order to get a virtual, enlarg
alexandr402 [8]

Answer:

Object should be placed at a distance, u = 7.8 cm

Given:

focal length of convex lens, F = 16.5 cm

magnification, m = 1.90

Solution:

Magnification of lens, m = -\frac{v}{u}

where

u = object distance

v = image distance

Now,

1.90 = \frac{v}{u}

v = - 1.90u

To calculate the object distance, u by lens maker formula given by:

\frac{1}{F} = \frac{1}{u}+ \frac{1}{v}

\frac{1}{16.5} = \frac{1}{u}+ \frac{1}{- 1.90u}

\frac{1}{16.5} = \frac{1.90 - 1}{1.90u}

\frac{1}{16.5} = \frac{ 0.90}{1.90u}

u = 7.8 cm

Object should be placed at a distance of 7.8 cm on the axis of the lens to get virtual and enlarged image.

6 0
3 years ago
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