Question

When a ball is thrown straight up, by how much does the speed decrease each second? Neglect air resistance.

Answer 1

Answer:

10ms⁻¹

Explanation:

Simply we can consider a motion equation

V = U + a*t

• v - final velocity
• u - initial velocity
• a-acceleration
• t - time

since in upward motion velocity decreases ,

amount of velocity decreased = u-v

V=U -gt ( g =10ms⁻² downwards)

u-v =10*1 ms⁻¹

decreased amount of velocity in a second = 10ms⁻¹