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gtnhenbr [62]
3 years ago
16

A 12 volt car battery pushes a charge through the headlight circuit with a resistance of 8.5 ohms. How much current is passing t

hrough the circuit
Physics
1 answer:
Illusion [34]3 years ago
8 0
Data:
i (current) = ? (Amps)
R (resistance) = 8.5 Ω
V (voltage) = 12 volts

Formula:
V = R*i\to \boxed{i =  \frac{V}{R} }

Solving:
i = \frac{V}{R}
i = \frac{12}{8.5}
\boxed{\boxed{i \approx 1.41\:Amps}}\end{array}}\qquad\quad\checkmark
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Svetradugi [14.3K]

Answer:

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3 years ago
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The circuits, P and Q, show two different ammeter-voltmeter methods of measuring resistance. Suppose the ammeter has a resistanc
qaws [65]

Answer:

Uncorrected values for

For circuit P

R = 2.4 ohm

For circuit Q

R = 2.4 ohm

Corrected values

for circuit P

R = 12 OHM

For circuit Q

R = 2.3 ohm

Explanation:

Given data:

Ammeter resistance 0.10 ohms

Resister resistance 3.0 ohms

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ammeter reads 2.5 amp

UNCORRECTED VALUES FOR

1) circuit P

we know that IR =V

R = \frac{6}{2.5} - 2.4 ohm

2) circuit Q

R = 2.4 ohm as no potential drop across ammeter

CORRECTED VALUES FOR

1) circuit p

IR = V

\frac{3R}{R+3} \times 2.5 = 6

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2) circuit Q

I\times (R+0.1) =V

R+0.1 =\frac{6}{2.5}

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3 years ago
If a cart of 10 kg mass has a force of 5 newtons exerted on it, what is its acceleration? m/s2
Elza [17]

Answer:

= 0.5 m/s²

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<em>Thus; a = F/m</em>

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<em>  a = 5 /10</em>

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3 years ago
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Answer:

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Cadences.

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