<u>Answer:</u> The molarity of solution will be 0.049 M
<u>Explanation:</u>
Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:
We are given:
Given mass of sodium chloride = 10 g
Molar mass of sodium chloride = 58.44 g/mol
Volume of solution = 3.50 L
Putting values in above equation:
Hence, the molarity of solution will be 0.049 M
Colligative
properties calculations are used for this type of problem. Calculations are as
follows:<span>
ΔT(freezing point) = (Kf)m
ΔT(freezing point)
= 1.86 °C kg / mol (0.50 mol/kg)
ΔT(freezing point) = 0.93 °C
Tf - T = 0.93 °C
<span>T = -0.93 °C</span></span>
Answer:
Diazanium sulfate is the correct answer.
Explanation:
Hope this helped Mark BRAINLIEST!!
Answer:
The answer to your question is FeS₃
Explanation:
Data
mass of Fe = 3.78g
mass of S = 5.95 g
mass of FeS
Chemical Balanced Reaction
Fe + S ⇒ FeS
Process
1.- Convert the grams to moles
For Iron
55.85g of Fe -------------- 1 mol
3.78 g of Fe ----------- x
x = (3.78 x 1) / 55.85
x = 0.0677 moles
For Sulfur
32 g of S ------------------- 1 mol
5.95 g ------------------ x
x = (5.95 x 1)/32
x = 0.185 moles
2.- Divide by the lowest number of moles
Iron = 0.0677 /0.0677 = 1
Sulfur = 0.185 /0.0677 = 2.73 ≈ 3
3.- Write the empirical formula
FeS₃
Answer:
Explanation:
The relation between equilibrium constant and Ecell is given below .
E⁰cell = (RT / nF ) lnK , F is faraday constant T is 273 + 25 = 298 K
E⁰cell = 1.46 - 1.21 = .25 V
n = 2
Putting the values
.25 = (8.314 x 298 lnK) / (2 x 96485 )
lnK = 19.47
K = 2.85 x 10⁸
2 )
Change in free energy Δ G
Δ G ⁰ = nE⁰ F
n = 4
E⁰ = .4 + .83 = 1.23 V
Δ G ⁰= 4 x 1.23 x 96485
= 474706 J / mol
3 )
E⁰cell = (RT / nF ) lnK
n = 2
1.78 = 8.314 x 298 lnK / 2 x 96485
lnK = 138.638
K = 1.62 x 10⁶⁰
