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3 years ago

A charge of 90 C passes through a wire in 1 hour 15 minutes . what is the current in the wire

2 answers:

dsp733 years ago

7 0

Current = C / seconds.

1 hour = 3600 seconds
15 minutes = 900 seconds

1 hour 15 minutes = 4500 seconds

90 C / 4500 sec = 0.02 amperes = 20 milliamperes

timurjin [86]3 years ago

5 0

We calculate current from the formula:
$I= \frac{q}{t}$ , where q is a electric charge transferred over time t
Time should be converted to seconds:
1h 15 min= 75min= 4500s
I= $\frac{90C}{4500s}=0,02A$ Result is in unit-Ampere

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A hydrogen discharge lamp emits light with two prominent wavelengths: 656 nm (red) and 486 nm (blue). The light enters a flint-g

mezya [45]

Answer:

The angle between the red and blue light is 1.7°.

Explanation:

Given that,

Wavelength of red = 656 nm

Wavelength of blue = 486 nm

Angle = 37°

Suppose we need to find the angle between the red and blue light as it leaves the prism

$n_{r}=1.572$

$n_{b}=1.587$

We need to calculate the angle for red wavelength

Using Snell's law,

$n_{r}\sin\theta_{i}=n_{a}\sin\theta_{r}$

Put the value into the formula

$1.572\sin37=1\times\sin\theta_{r}$

$\theta_{r}=\sin^{-1}(\dfrac{1.572\sin37}{1})$

$\theta_{r}=71.0^{\circ}$

We need to calculate the angle for blue wavelength

Using Snell's law,

$n_{b}\sin\theta_{i}=n_{a}\sin\theta_{b}$

Put the value into the formula

$1.587\sin37=1\times\sin\theta_{b}$

$\theta_{b}=\sin^{-1}(\dfrac{1.587\sin37}{1})$

$\theta_{b}=72.7^{\circ}$

We need to calculate the angle between the red and blue light

Using formula of angle

$\Delta \theta=\theta_{b}-\theta_{r}$

Put the value into the formula

$\Delta \theta=72.7-71.0$

$\Delta \theta=1.7^{\circ}$

Hence, The angle between the red and blue light is 1.7°.

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Answer:

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