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3 years ago

select the correct scientific notation form of this numeral 541 5 * 10^2 5.4 * 10^2 5.4 * 10^2 5.0 * 10^2

1 answer:

7 0

To find the scientific notation, you need to divide at the decimal by the power of 10. So since there are 2 powers of 10, what you want to do is move the decimal 2 places to the left which will give you: .054

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Greg is in a car at the top of a roller-coaster ride. The distance, d, of the car from the ground as the car descends is determi

Talja [164]

The solution to the problem is as follows:

<span>Average = 80
So Sum = 80 * 5 = 400
Mode = 88, so two results are 88 (if three results were 88, then the median would be 88).
Three results are 81, 88, and 88.
That leaves 143. We could still have one 81 score, so that leaves the lowest score as 62.

Greg is in a car at the top of a roller-coaster ride. The distance, d, of the car from the ground as the car descends is determined by the equation d = 144 - 16t2, where t is the number of seconds it takes the car to travel down to each point on the ride. How many seconds will it take Greg to reach the ground?
d = 144 - 16t2
0 = 144 - 16t2
16t^2=144
t^2=9
t=3</span>

3 0

3 years ago

An object experiences an impulse, moves and attains a momentum of 200 kg·m/s. If its mass is 50 kg, what is its velocity?

Nady [450]

Answer:

4 m/s

Explanation:

Momentum is defined as:

$p=mv$

where

m is the mass of the object

v is its velocity

For the object in this problem, we know:

p = 200 kg m/s is the momentum

m = 50 kg is the mass

Solving for the velocity, we find:

$v=\frac{p}{m}=\frac{200}{50}=4 m/s$

8 0

2 years ago

Please please help

dsp73

Answer:

true

Explanation:

The law of conservation of charge states that whenever electrons are transferred between objects, the total charge remains the same.

3 0

3 years ago

A 26.4 g silver ring (cp = 234 J/kg·°C) is heated to a temperature of 66.2°C and then placed in a calorimeter containing 4.94 ✕

Slav-nsk [51]

Answer:

The final temperature of the mixture = 64.834 °C.

Explanation:

Heat lost by the silver ring = heat gained by the water + heat transferred to the surrounding.

c₁m₁(t₁-t₃) = c₂m₂(t₃-t₂) + Q..............Equation 1

Where c₁ = specific heat capacity of the silver copper, m₁ = mass of the silver copper, t₁ = initial temperature of the silver copper, t₃ = final temperature of the mixture. c₂ = specific heat capacity of water, t₂ = initial temperature of water, m₂ = mass of water, Q = energy transferred to the surrounding.

making t₃ the subject of the equation,

t₃ = [c₁m₁t₁+c₂m₂t₂-Q]/(c₁m₁+c₂m₂)........................ Equation 2

Given: c₁ = 234 J/kg.°C, m₁ = 26.4 g, t₁ = 66.2 °C, c₂ = 4200 J/K.°C, m₂ = 4.92×10⁻² kg, t₂ = 24.0 °C, Q = 0.136 J.

Substituting into equation 2

t₃ = [(234×26.4×66.2)+(4200×0.0492×24)-0.136]/[(234×26.4)+(4200×0.0492)]

t₃ = (408957.12+4959.36-0.136)/(6177.6+206.64)

t₃ = (413916.48-0.136)/6384.24

t₃ = 413916.34/6384.24

Thus the final temperature of the mixture = 64.834 °C.

6 0

3 years ago

A person carries a box of 100 kg. What is the weight of the box? (g= 9.8 m/s2)

aliina [53]

Answer:

980 newton

Explanation:

100×9.8 = 980

8 0

2 years ago