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3 years ago

Define force ? ☹❣️️ Degine weight?

Physics

1 answer:

mylen [45]3 years ago

6 0

Explanation:

force is anything that allows a body to be in motion..

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The center of mass of a 0.30-kg (non-uniform) meter stick is located at its 45-cm mark. What is the magnitude of the torque (in

lbvjy [14]

Answer:

The magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.

Explanation:

Given that,

Mass of the meter stick, m = 0.3 kg

Center of mass is located at its 45 cm mark.

We need to find the magnitude of the torque due to gravity if it is supported at the 28-cm mark. Torque acting on the object is given by :

$\tau=r\times F\\\\\tau=(45-28)\times 10^{-2}\times 0.3\times 9.79\\\\\tau=0.499\ N-m$

$\tau=0.5\ N-m$

So, the magnitude of the torque due to gravity if it is supported at the 28-cm mark is 0.5 N-m.

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4 years ago

Like the filters falling through the air, a car on the freeway represents an object with a high Reynolds number traveling throug

Goshia [24]

Answer:

ΔF=125.22 %

Explanation:

We know that drag force on the car given as

$F_D=\dfrac{1}{2}\rho C_DA v^2$

$C_D$ =Drag coefficient

A=Projected area

v=Velocity

ρ=Density

All other quantity are constant so we can say that drag force and velocity can be given as

$\dfrac{F_D_1}{F_D_2}=\dfrac{v_1^2}{v_2^2}$

Now by putting the values

$\dfrac{F_D_1}{F_D_2}=\dfrac{v_1^2}{v_2^2}$

$\dfrac{F_D_1}{F_D_2}=\dfrac{50^2}{75^2}$

$\dfrac{F_D_1}{F_D_2}=0.444$

Percentage Change in the drag force

$\Delta F=\dfrac{F_D_2-F_D_1}{F_D_1}\times 100$

$\Delta F=\dfrac{F_D_2-0.444F_D_2}{0.444F_D_2}\times 100$

$\Delta F=\dfrac{1-0.444}{0.444}\times 100$

ΔF=125.22 %

Therefore force will increase by 125.22 %.

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3 years ago

Cell with structures labeled A, B, and C

sveticcg [70]

The answer is A. :)

6 0

3 years ago

Read 2 more answers

What is the relationship between earths spheres and matter?

Rainbow [258]

<span>Don't know what you mean by Earths Spheres. The Earth is a sphere -- singular. And it is made up of LOTS of matter</span>

5 0

4 years ago

g) If two cars A and B are moving with velocity 60 km/hr and 80 km/hr respectively in the same direction. What will be the relat

tester [92]

Explanation:

Here,

Velocity of A=60km/hr

Velocity of B=80km/hr

Now,

Relative velocity of B with respect to A in the same direction=Velocity of B - Velocity of A

=80km/hr-60km/hr

=20km/hr

4 0

2 years ago

Define force ? ☹❣️️ Degine weight? ​

Define force ? ☹❣️️ Degine weight?