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poizon [28]
3 years ago
10

Select the correct location on the image

Chemistry
2 answers:
Lubov Fominskaja [6]3 years ago
8 0

Answer: 3p4, the first box of the 3p orbital

Explanation:

Lera25 [3.4K]3 years ago
7 0

The orbital filled by the last electron from the S element is 3p

<h3>Further explanation </h3>

In an atom there are levels of energy in the skin and sub skin.

This energy level is expressed in the form of electron configurations.

Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub skins in the skin of an atom, namely s, p, d and f. The maximum number of electrons for each sub skin is

• s: 2 electrons

• p: 6 electrons

• d: 10 electrons and

• f: 14 electrons

Charging electrons in the sub skin uses the following sequence:

<em>1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc. </em>

Each sub-skin also has an orbital depicted in the form of a square in which there are electrons symbolized by half arrows.

Each orbital in an atom consists of 4 quantum numbers:

  • n is the principal quantum number.
  • l is the angular momentum / azimuthal quantum number
  • ml, the magnetic quantum number
  • ms, the electron-spin quantum number

Value of n: positive integer

value of l: s = 0, p = 1, d = 2, f = 3, ... (n-1)

ml value: between -l to + l

ms value: +1/2 or -1/2

An sulfur atom (S) has 16 electrons means having an electron configuration as follows:

1s², 2s², 2p⁶, 3s², 3p⁴

or we can write with the noble gas symbol

[Ne] 3s² 3p⁴

From this configuration, it has been seen that the last electron (16th electron) occupies a 3p orbital (3p⁴) orbital with a downward symbol

The quantum number:

n = 3

l = 1

ml = -1

ms = -1/2

<h3>Learn more </h3>

electron transitions

brainly.com/question/2079874

the locations and properties of two electrons

brainly.com/question/2292596

It's sublevel

brainly.com/question/4520082

a possible full set of quantum numbers

brainly.com/question/5389767

Keywords: orbitals, subshells, quantum numbers

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Consider the following reaction: 4Fe + 302 → 2Fe2O3. What mass of iron(III) oxide would
frutty [35]

Answer:

Mass = 357.7 g

Explanation:

Given data:

Mass of Fe =  250 g

Mass of oxygen = 120 g

Mass of iron(III) oxide produced = ?

Solution:

Chemical equation:

4Fe + 3O₂        →     2Fe₂O₃

Number of moles of Fe:

Number of moles = mass/molar mass

Number of moles = 250 g/ 55.8 g/mol

Number of moles = 4.48 mol

Number of moles of O₂ :

Number of moles = mass/molar mass

Number of moles = 120 g/ 32 g/mol

Number of moles = 3.75 mol

Now we will compare the moles of reactants with product.

        Fe          :          Fe₂O₃

        4            :             2

      4.48         :        2/4×4.48 = 2.24

        O₂          :          Fe₂O₃

        3            :             2

      3.75         :        2/3×3.75= 2.5

Less number of moles of Fe₂O₃ are produced by Fe thus it will act as limiting reactant.

Mass of Fe₂O₃:

Mass = number of moles × molar mass

Mass = 2.24 mol × 159.69 g/mol

Mass = 357.7 g

3 0
3 years ago
7.5 moles of nitrogen gas (N2) is formed in the following reaction. How many grams
AfilCa [17]

Answer:

Mass = 255 g

Explanation:

Given data:

Number of moles of nitrogen = 7.5 mol

Mass of ammonia formed = ?

Solution:

Chemical equation:

3H₂ + N₂      →    2NH₃

Now we will compare the moles of nitrogen and ammonia.

             N₂         :        NH₃

               1          :         2

              7.5       :       2/1×7.5 = 15

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 15 mol × 17 g/mol

Mass = 255 g

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Cerrena [4.2K]

Mn metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe. So, the correct option is (c) Mn.

Commonly, sacrificial electrodes are employed to stop another metal from corroding or oxidising. A metal that is more reactive than the metal being shielded must serve as the sacrificial electrode. Magnesium, aluminium, and zinc are the three metals most frequently used in sacrificial anodes.

Manganese-Magnesium (Mn-Mg) electrode is more suited for on-shore pipelines where the electrolyte (soil or water) resistivity is higher since it has the highest negative electropotential of the three. In order to replenish any electrons that could have been lost during the oxidation of the shielded metal, the highly active metal offers its electrons.

Therefore, Mn metal can be used as a sacrificial electrode to prevent the rusting of an iron pipe. So, the correct option is (c) Mn.

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