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DochEvi [55]
3 years ago
8

Which substance in the reaction is the acid? HCI KOH KCI H20

Chemistry
1 answer:
finlep [7]3 years ago
3 0
It is d i believe hope this helps
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Which label belongs in the area marked X? can reproduce by budding can reproduce by fragmentation with regeneration reproduce in
marusya05 [52]

Answer:

Nucleus.

Explanation:

The sponge is a multicellular organism that consists of pores that allows water to move through the body. Sponges belong to the kingdom Animalia and phylum Porifera. Sponges can reproduce by budding. Sponges are placed in kingdom Animalia because they are unable to make their own food, made of more than one cell, and absence of cell wall.

4 0
2 years ago
Where is desertification likely to occur?
viktelen [127]
I think in drylands, drylands are particularly affected by desertification.
5 0
3 years ago
Read 2 more answers
If the H3O is 4.950 x 10-12 what is the ph?
romanna [79]

Answer:

pH = 11.3

Explanation:

From the question given above, the following data were obtained:

Concentration of hydronium ion [H₃O⁺] = 4.950×10¯¹² M

pH =.?

The pH of a solution is defined by the following equation:

pH = –Log [H₃O⁺]

Thus, with the above formula, we can obtain the pH of the solution as follow:

Concentration of hydronium ion [H₃O⁺] = 4.950×10¯¹² M

pH =.?

pH = –Log [H₃O⁺]

pH = –Log 4.950×10¯¹²

pH = 11.3

8 0
3 years ago
A compound that has a sea of delocalized electrons has what type of bonding?
Anarel [89]

Answer:

Metallic Bonding

Explanation:

Metallic Bonding

In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “sea” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions.

8 0
3 years ago
Molecule contains carbon, hydrogen and sulfur atoms. When a sample of 0.535g of this compound is burnt in oxygen, 1.119 g of CO2
OLga [1]

Answer:

The empirical formula is, C4H4S

Explanation:

Number of moles of carbon = 1.119 g/ 44g/mol = 0.025 moles

Mass of Carbon= 0.025 moles × 12 g/ mole = 0.3 g

Number of moles of hydrogen = 0.229/18g/mol × 2 = 0.025 moles

Mass of hydrogen = 0.025 moles × 1 = 0.025 g

Number of moles of sulphur = 0.407g/ 64 g/mol = 0.0064 moles

Mass of sulphur= 0.0064 moles ×32 = 0.2 g

Now we obtain the mole ratios by dividing through by the lowest ratio.

C- 0.025 moles/ 0.0064 moles, H- 0.025 moles/ 0.0064 moles, S- 0.0064 moles/0.0064 moles

C4H4S

4 0
2 years ago
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