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Bad White [126]
3 years ago
14

What is the temperature of 0.750 mol of a gas stored in a 6,850 mL cylinder at 2.21 atm? A: 2.95 K

Chemistry
2 answers:
harina [27]3 years ago
8 0

Option D: 246 K

According to ideal gas law:

PV=nRT ...... (1)

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature of the gas. The value of R is 0.082 atm L K^{-1}mol^{-1}.

Number of moles of gas are 0.750 mol, volume of cylinder is 6850 mL and pressure of gas is 2.21 atm.

First converting volume from mL to L

1 mL=10^{-3}L

Thus,

6850 mL=6.850 L

Putting the values in equation (1),

(2.21 atm)(6.850 L)=(0.750 mol)(0.082 atm L K^{-1}mol^{-1}T

Rearranging

T=\frac{(2.21 atm)(6.850 L)}{(0.750 mol)(0.082 atm L K^{-1}mol^{-1})}=246 K,

Therefore, temperature of the gas is 246 K.


vredina [299]3 years ago
6 0
D is the correct answer
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