Answer:
0.005 mol
Explanation:
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
w = given mass of Gold = 1.05 g ,
m = molecular mass of Gold = 197 g/mol
<u>Hence , moles can be calculated as -</u>
n = w / m
= 1.05 g / 197 g/mol = 0.005 mol
Answer:
Explanation:
Formula
% = (dicots/angiosperms) * 100
Givens
angiosperms (total) = 260000
Dicots = 195000
Solution
% = (195000/260000) * 100
% = 0.75 * 100
Answer: % = 75% are dicots
Answer:
the right side of the periodic table are metals while the left side are non metals (with the exception of hydrogen)
<span>_____Balanced Chemical eqn___
C6H5OH + 7O2 --> 6C02 + 3H20
Firstly, heat of rxn will be absorbed by bobm calorimaeter, so find the qcal
qcal = CΔT
= (11.66 KJ/°C)(26.37°C- 21.36°C)
= 58.42 KJ
since the heat of rxn absorbed by calorimeter, assume:
qrnx = -qcal
= - 58.42 KJ
_____q GRAM OF C6H5OH______
Find the number of moles you have by dividing the given grams of C6H5OH by its molar mass
(1.8 g C6H5OH)(94 g/mole C6H5OH) = 0.0191 mol C6H5OH
then divide qrnx by the number of moles.
(-58.42 KJ)/(0.0191 mol C6H5OH) = -3058.64 KJ/mol C6H50H</span>
It might directly convert into a photoelectric effect like a solar panel. Alternatively, it may be transformed first into mechanical energy, as in boiling a working fluid and powering a turbine, or it could be transformed into chemical energy, as in photosynthesis, which grows trees and then burns the wood to power a steam engine and generator.
<h3> Photoelectric effect:-</h3>
Electrons are released when a material is exposed to electromagnetic radiation, such as light, known as the photoelectric effect. These electrons are referred to as photoelectrons. To derive conclusions regarding the properties of atoms, molecules, and solids, the phenomena are researched in condensed matter physics, solid state chemistry, and quantum chemistry. Electronic devices designed for light sensing and precisely timed electron emission have found usage for the effect.
Learn more about the Photoelectric effect here:-
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