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Sergeu [11.5K]
3 years ago
13

Which of the following is an example of cohesion?

Chemistry
1 answer:
Sunny_sXe [5.5K]3 years ago
5 0
Where are the examples
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Herbivores are animals that eat plants. Carnivores are animals that eat other animals. The table shows data about several carniv
Tanzania [10]

Answer:

A.  Herbivores have longer digestive systems than carnivores have.

Explanation:

We can conclude that the herbivores have longer digestive systems compared to carnivores.

Carnivores feeds on other animals whereas herbivores eats plants.

  • Most herbivores have a four stomach compartment system that helps them process and digest their food.
  • This is because they have to process cellulose in plants which needs to be properly broken down.
  • Flesh eating carnivores do not require this arrangement.
  • The four stomach compartment of most herbivores includes Rumen, Reticulum, omasum and abomasum.
  • They also chew the cud whereby they regurgitate food materials.
4 0
3 years ago
Read 2 more answers
A "fizz-keeper" is a small air pump that you can place on an opened soda bottle. When operated the pump is used to pressurize th
AnnZ [28]

Answer: increase

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

As soda contains carbon dioxide dissolved in water.

The equation given by Henry's law is:

C_{CO_2}=K_H\times p_{CO_2}

where,

C_{CO_2} = solubility of carbon dioxide in water

K_H = Henry's constant

p_{CO_2} = partial pressure of carbon dioxide

Thus on increasing the pressure, the solubility of carbon dioxide also increase.

3 0
3 years ago
While ethanol (CH3CH2OH) is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by
grin007 [14]

Answer:

n_{C2H_5OH}^{eq}=14.234mol

Explanation:

Hello,

In this case, the reaction is:

C_2H_4+H_2O\rightleftharpoons CH_3CH_2OH

Thus, the law of mass action turns out:

Kc=\frac{[CH_3CH_2OH]_{eq}}{[H_2O]_{eq}[CH_2CH_2]_{eq}}

Thus, since at the beginning there are 29 moles of ethylene and once the equilibrium is reached, there are 16 moles of ethylene, the change x result:

[CH_2CH_2]_{eq}=29mol-x=16mol\\x=29-16=13mol

In such a way, the equilibrium constant is then:

Kc=\frac{\frac{x}{V} }{\frac{16mol}{V}* \frac{3mol}{V}} =\frac{\frac{13mol}{75.0L} }{\frac{16mol}{75.0L}* \frac{3mol}{75.0L}} =20.31

Thereby, the initial moles for the second equilibrium are modified as shown on the denominator in the modified law of mass action by considering the added 15 moles of ethylene:

Kc=\frac{\frac{13+x_2}{V} }{\frac{16+15-x_2}{V}* \frac{3-x_2}{V}}  =20.31

Thus, the second change, x_2 finally result (solving by solver or quadratic equation):

x_2=1.234mol

Finally, such second change equals the moles of ethanol after equilibrium based on the stoichiometry:

n_{C2H_5OH}^{eq}=x+x_2=13mol+1.234mol\\n_{C2H_5OH}^{eq}=14.234mol

Best regards.

5 0
3 years ago
Identify the four parts of the potential energy diagram.
Fed [463]

I think this is how to do it. but I'm sorry if it's not exactly right

4 0
3 years ago
Read 2 more answers
Please answer! I don't understand this so I need explanation.
Ganezh [65]

Answer:

  1.2×10^7 dm³

Explanation:

1 mole of sulfur dioxide weighs 64 grams, so 64 tonnes is 10^6 moles.

The reaction of interest is ...

  2SO₂ +O₂ ⇆ 2SO₃

This reaction uses half as many moles of oxygen as of sulfur dioxide. That is, 5×10^5 moles of oxygen are required. That quantity will have a volume of ...

  (5×10^5 mol)(24 dm³/mol) = 1.2×10^7 dm³ . . . volume of oxygen needed

4 0
3 years ago
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