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mylen [45]
3 years ago
7

The velocity of a 1.3 kg remote-controlled car is plotted on the graph. The work of segment A is J.

Physics
2 answers:
tamaranim1 [39]3 years ago
5 0

Answer: 585 J

Explanation:

We can calculate the work done during segment A by using the work-energy theorem, which states that the work done is equal to the gain in kinetic energy of the object:

W=K_f -K_i

where Kf is the final kinetic energy and Ki the initial kinetic energy. The initial kinetic energy is zero (because the initial velocity is 0), while the final kinetic energy is

K_f =\frac{1}{2}mv^2

The mass is m=1.3 kg, while the final velocity is v=30 m/s, so the work done is:

W=K_f = \frac{1}{2}(1.3 kg)(30 m/s)^2=585 J

3241004551 [841]3 years ago
5 0
585 J

This is how to get this anwer:
1/2 * 1.3 * (30^2) = 
0.65 * 900 = 585 K=J

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