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3 years ago

This scientific tool measures _ in the metric units of

Physics

1 answer:

ladessa [460]3 years ago

8 0

Answer:

<em>MASS,GRAMS </em>

Explanation:

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if a spring stores 5j of energy when it is compressed by0.5m,what is the spring constant of the spring?

Sindrei [870]

Answer:

K = 40N/m

Explanation:

According to Hooke’s law

Energy = 1/2 kx^2

K is the spring constant

x = displacement

From the question

Energy =5J

x = 0.5m

K = ?

Using the above formula,

We have

5 = 1/2 x k x (0.5)^2

5 = 1/2 x k x (0.5 x 0.5)

5 = 1/2 x k x 0.25

5 = 0.25k/ 2

Cross multiply

5 x 2 = 0.25k

10 = 0.25k

Divide both sides by 0.25 to get k

10/0.25 = 0.25k/ 0.25

40 = k

K = 40N/m

5 0

3 years ago

50POINTS! What is the escape velocity for lunar module? Lunar module mass 15,200 kg radius of moon 1.74x106m, mass of moon 7.34x

Airida [17]

Answer:

2.73 km/s

Explanation:

The escape velocity of an object in the gravitational field of the moon is (on the surface of the planet)

$v=\sqrt{\frac{2GM}{r}}$

where

$G=6.67\cdot 10^{-11} m^3 kg^{-1} s^{-2}$ is the gravitational constant

$M=7.34\cdot 10^{22} kg$ is the mass of the Moon

$r=1.74\cdot 10^6 m$ is the radius of the Moon

As we can see, the escape velocity does not depend on the mass of the lunar module.

Substituting the numbers into the formula, we find

$v=\sqrt{\frac{2(6.67\cdot 10^{-11})(7.34\cdot 10^{22}kg)}{(1.74\cdot 10^6 m)}}=2732 m/s=2.73 km/s$

7 0

3 years ago

Read 2 more answers

Assume that segment r exerts a force of magnitude t on segment l. what is the magnitude flr of the force exerted on segment r by

mrs_skeptik [129]

If we are talking on the force being exerted by a segment of a rope of lenght R on the right on a point M which is being also pulled from the Left by a segment of rope R as shown in the figure attached. Then we invoke Newton's Third Law:
"Any force exerted by an object (in this case a segment of the rope) also suffers a equal and opposite force".
If we pick $T_R=T$ whis is the tension exerted by the right segment then the left segment will also exert an equal and opposite force so we have that $T_L=-T$