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Sergio039 [100]
2 years ago
12

I need help with this question, could you help me? :))) ASAP

Physics
1 answer:
Pepsi [2]2 years ago
4 0
Oh ya the correct answer for this is B I think because structure B
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A solid block is attached to a spring scale. When the block is suspended in air, the scale reads 20.1 N; when it is completely i
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Answer:

A) V = 4.92 \cdot 10^{-4} m^{3} = 492 cm^{3}

B) d = 4181.49 kg/m^{3} = 4.18 g/cm^{3}

Explanation:

A) Using the Archimedes' force we can find the weight of water displaced:

W_{d} = W_{a} - W_{w}

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W_{a}: is the weight of the block in the air = 20.1 N

W_{w}: is the weight of the block in the water = 15.3 N

W_{d} = W_{a} - W_{w} = 20.1 N - 15.3 N = 4.8 N

Now, the mass of the water displaced is:

m = \frac{W_{d}}{g} = \frac{4.8 N}{9.81 m/s^{2}} = 0.49 kg

The volume of the block can be found using the mass of water displaced and the density of the water:

V = \frac{m}{d} = \frac{0.49 kg}{997 kg/m^{3}} = 4.92 \cdot 10^{-4} m^{3} = 492 cm^{3}

B) The density of the block can be found as follows:

d = \frac{W_{a}}{g*V} = \frac{20.1 N}{9.81 m/s^{2}*4.92 \cdot 10^{-4} m^{3}} = 4181.49 kg/m^{3} = 4.18 g/cm^{3}

I hope it helps you!            

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