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babunello [35]
2 years ago
6

The loudness of a sound depends on the sound wave's ________. A. frequency B. pitch C. amplitude D. density

Physics
2 answers:
Archy [21]2 years ago
3 0
The answer is C.amplitude
kirill [66]2 years ago
3 0

Answer:

Frequency or amplitude

Explanation:

nun

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11. Two point charges, initially 1 cm apart, are moved to a distance of 3 cm apart. By what factor
vampirchik [111]

Answer:

9

Explanation:

8 0
3 years ago
A.) Determine the work done by Zach on the bull.
Lana71 [14]

Explanation:

Work done is a physical quantity that is defined as the force applied to move a body through a particular distance.

Work is only done when the force applied moves a body through a distance.

    Work done  = Force x distance

The maximum work is done when the force is parallel to the distance direction.

The minimum work is done when the force is at an angle of 90° to the distance direction.

 So to solve this problem;

 multiply the force applied by Zack and distance through which the bull was pulled.

3 0
2 years ago
Why are there only two elements in the first period of the periodic table?(1 point)
svetlana [45]

Answer:

because only two electrons can fit in the first orbit around the nucleus, and each period on the table is organized by number of orbits

5 0
2 years ago
Which two surfaces would have the highest coefficient of friction?
scoray [572]
<span>1. sandpaper against wood. 
2. rubber mat against the floor of the shower stall.

</span><span># High coefficient of friction describes the degree of interaction between two surfaces. . A higher coefficient of friction indicates that two surfaces in contact have a greater resistance.</span>
5 0
3 years ago
Read 2 more answers
3. A large crane lifts a 25,000 kg mass in the air. The amount of work that must be done by the
andreev551 [17]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the concept of Efficiency.

Here we can see that, the Input work is given as 2.2 x 10^7 J and the efficiency is given as 22%

The efficiency is => 22% => 22/100.

so we get as,

E = W(output) /W(input)

hence, W(output) = E x W(input)

so we get as,

W(output) = (22/100) x 2.2 x 10^7

=> W(output) = 0.22 x 2.2 x 10^7 => 0.484 x 10^7

hence, W(output) = 4.84 x 10^6 J

The useful work done on the mass is 4.84 x 10^6 J

5 0
2 years ago
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