Answer:
0.0468 g.
Explanation:
- The decay of radioactive elements obeys first-order kinetics.
- For a first-order reaction: k = ln2/(t1/2) = 0.693/(t1/2).
Where, k is the rate constant of the reaction.
t1/2 is the half-life time of the reaction (t1/2 = 1620 years).
∴ k = ln2/(t1/2) = 0.693/(1620 years) = 4.28 x 10⁻⁴ year⁻¹.
- For first-order reaction: <em>kt = lna/(a-x).</em>
where, k is the rate constant of the reaction (k = 4.28 x 10⁻⁴ year⁻¹).
t is the time of the reaction (t = t1/2 x 8 = 1620 years x 8 = 12960 year).
a is the initial concentration (a = 12.0 g).
(a-x) is the remaining concentration.
∴ kt = lna/(a-x)
(4.28 x 10⁻⁴ year⁻¹)(12960 year) = ln(12)/(a-x).
5.54688 = ln(12)/(a-x).
Taking e for the both sides:
256.34 = (12)/(a-x).
<em>∴ (a-x) = 12/256.34 = 0.0468 g.</em>
Answer:
copper
Explanation:
it's on the periodic table of elements
The complete chemical formula for the unknown compound is N2O3 where X = 2 which is the oxidation state of oxygen.
<h3>What is oxidation state?</h3>
Oxidation state is the number of electron which the compound is giving or taking from each other to form the bonds as the oxidation is hight oxidation is happening asn if the low then reduction is happening.
In the compound N2O3 the oxidation state of O is 2 and the oxidation stte of N is 3 written in the cross-cross manner in compound.
Therefore, N2O3 where X = 2 which is the oxidation state of oxygen is complete chemical formula for the unknown compound.
Learn more about oxidation state, here:
brainly.com/question/12320652
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