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aliya0001 [1]
4 years ago
6

12. Which of the following statements is true about a nickel-cadmium dry cell? (Points : 3) The cathode reaction is Cd + 2OH Cd(

OH)2 + 2e. The cathode reaction is Cd + NiO2 + 2H2O Cd(OH)2 + Ni(OH)2. The cathode reaction is NiO2+ H2O + 2e Ni(OH)2 + 2OH. The anode reaction is NiO2 + H2O + 2e Ni(OH)2 + 2OH.
Chemistry
1 answer:
ella [17]4 years ago
5 0
The correct answer among the options given is the first one. The cathode reaction for a nickel-cadmium dry cell is Cd + 2OH Cd(OH)2 + 2e. It should be remembered that at the cathode reduction always happen and reduction is the gain of electrons. As we can see from the half reaction, there is a gain of 2 electrons.
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Whitepunk [10]

Hi!

<u>Answer: 1ml of NaOH and 49 ml of Water</u>

Concentration of NaOH to make: 0.001 M ( C1 )

Volume of NaOH to make: 50 ml ( V1 )

Concentration of NaOH in stock: 0.05 M ( C2 )

Volume of stock to use: V2

Using the formula C1 V1 = C2 V2 which is the standard formula for determining the dilutions to acquire a specified volume and concentration, we get:

0.001 M x 50 ml = 0.05 M x V2

V2 = 1 ml

<em>So using 1ml of 0.05 M NaOH and 49 ml of Water</em>

<h3>Hope this helps</h3>

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4 years ago
When does a real gas behave like an ideal gas?
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At high temperatures and low pressures

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Which alkane is the isomer of butane called 2-methylpropane?
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Isomers have same formula but the different arrangement of atoms/ structure.

<span>Butane is an alkane which has 4 carbon atoms. The formula is C4H10. 2-methyl propane is also an alkane which has 4 carbon atoms. The formula is also C4H10. Only difference in these compounds is 2-methyl propane has 3 carbon atoms in main carbon chain and there is CH3- group in 2nd C atom while butane has 4 carbon atoms in main carbon chain. </span>

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Que masa de metano y oxigeno se necesitan para obtener 60gr de dioxido de carbono?
frez [133]

Answer:

\large \boxed{\text{22 g methane; 60 g oxygen}}

Explanation:

1. Gather the information

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:  16.04      32.00        44.01

        CH₄   +   2O₂   ⟶   CO₂   +   2H₂O

m/g:                                   60

 

1. Moles of CO₂

\text{Moles of CO}_{2} = \text{60 g CO}_{2} \times \dfrac{\text{1 mol CO}_{2}}{\text{44.01 g CO}_{2}} = \text{1.36 mol CO}_{2}

2. Mass of CH₄

(a) Moles of CH₄

\text{Moles of CH}_{4} = \text{1.36 mol CO}_{2} \times \dfrac{\text{1 mol CH}_{4}}{\text{1 mol CO}_{2}} = \text{1.36 mol CH}_{4}

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\text{Mass of CH}_{4} = \text{1.36 mol CH}_{4} \times \dfrac{\text{16.04 g CH}_{4}}{\text{1 mol CH}_{4}} = \textbf{22 g CH}_{4}\\\\\text{The mass of CH$_{4}$ required is $\large \boxed{\textbf{22 g}}$}

3. Mass of O₂ required

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(b) Mass of O₂

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8 0
3 years ago
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