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aliya0001 [1]
3 years ago
6

12. Which of the following statements is true about a nickel-cadmium dry cell? (Points : 3) The cathode reaction is Cd + 2OH Cd(

OH)2 + 2e. The cathode reaction is Cd + NiO2 + 2H2O Cd(OH)2 + Ni(OH)2. The cathode reaction is NiO2+ H2O + 2e Ni(OH)2 + 2OH. The anode reaction is NiO2 + H2O + 2e Ni(OH)2 + 2OH.
Chemistry
1 answer:
ella [17]3 years ago
5 0
The correct answer among the options given is the first one. The cathode reaction for a nickel-cadmium dry cell is Cd + 2OH Cd(OH)2 + 2e. It should be remembered that at the cathode reduction always happen and reduction is the gain of electrons. As we can see from the half reaction, there is a gain of 2 electrons.
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Solid potassium hydroxide koh decomposes into gaseous water and solid potassium oxide . write a balanced chemical equation for t
galina1969 [7]
<span>The chemical formula is pretty straightforward. 2KOH reacts to produce H2O and K2O. This is the balanced chemical reaction between: Solid potassium hydroxide koh decomposing into gaseous water and solid potassium.</span>
4 0
3 years ago
What substance is oxidized in the following reaction? 4HCl + MnO2 → Cl2 + 2H2O + MnCl2
Blizzard [7]

Answer:

Cl⁻ was oxidized.

Explanation:

  • 4HCl + MnO₂ → Cl₂ + 2H₂O + MnCl₂

Oxidation can be defined as the process in which the oxidation number of a substance increases.

On the left side of the equation, Cl has a charge of -1 (in HCl); while on the right side of the equation Cl has a charge of 0 in Cl₂.

Thus, Cl⁻ was oxidized.

8 0
3 years ago
In the sn2 experiment, what was the purpose of washing the distilled product with 5% naoh
photoshop1234 [79]

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5 0
3 years ago
The edge length of the unit cell of KCl (NaCl-like structure, FCC) is 6.28 Å. Assuming anion-cation contact along the cell edge,
Mila [183]

Answer:

1.33 Å

Explanation:

Given that the edge length , a of the KCl which forms the FCC lattice = 6.28 Å

Also,

For the FCC lattice in which the anion-cation contact along the cell edge , the ratio of the radius of the cation to that of anion is 0.731.

Thus,

\frac {r^+}{r^-}=0.731 .................1

Also, the sum of the radius of the cation and the anion in FCC is equal to half of the edge length.

Thus,

r^++r^-=\frac {a}{2}  ...................2

Given that:

Cl^-\ (r^-) = 1.82\ \dot{A}

To find,

K^+\ (r^+) = ? \dot{A}

Using 1 and 2 , we get:

1.731\ r^+=0.731\times \frac {6.28}{2}

<u>Size of the potassium ion = 1.33 Å</u>

4 0
3 years ago
Answer questions 2 and 3
nlexa [21]

Answer:

2:a-heterogenous

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d-heterogenous with water

3:Filtration is used to separate insoluble particles from a solution

Distillation is used to separate liquids with close but different boiling points e.g water and ethanol

Explanation:

2: homogenous mixtures form a uniform layer meaning that a mixture containing more than one layer is heterogenous

4 0
3 years ago
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