Answer:
When we say "chlorine wants to gain one electron", we speak of the radical atom. Chlorine as a free radical, Cl⋅ , is the chlorine atom that we say has 7 valence electrons and wants its 8th to form an octet. So, Cl⋅ , chlorine radical, is less stable, and Cl− , chlorine ion, is more stable
Answer:
Following are the responses to the given choices:
Explanation:
For point a:
Using the acid and base which are strong so,
moles of 
(from
)
moles of 
(from 
)
So, 
i.e. 
mol of 
in excess in total volume 
i.e. concentration of 
![p[OH^{-}] = -\log [OH^{-}] = -\log [2 \times 10^{-4}\ mol] = 3.70](https://tex.z-dn.net/?f=p%5BOH%5E%7B-%7D%5D%20%3D%20-%5Clog%20%5BOH%5E%7B-%7D%5D%20%3D%20-%5Clog%20%5B2%20%5Ctimes%2010%5E%7B-4%7D%5C%20mol%5D%20%3D%203.70)
Since, 
so,
For point b:
moles of = from point a 
moles of (from):
1 mol neutralizes 1 mol of
So, 
i.e. 
in excess in the total volume of 
i.e. concentration of
Hence, ![pH = -\log [H^+] = -\log[2 \times 10^{-4}] = 3.70](https://tex.z-dn.net/?f=pH%20%3D%20-%5Clog%20%5BH%5E%2B%5D%20%3D%20-%5Clog%5B2%20%5Ctimes%2010%5E%7B-4%7D%5D%20%3D%203.70)
Answer:
Option D. 1×10¯¹⁰ M
Explanation:
From the question given above, the following data were obtained:
pH = 10
Hydrogen ion concentration, [H+] =?
The hydrogen ion concentration, [H+] of the Ba(OH)2 solution can be obtained as follow:
pH = – Log [H+]
pH = 10
10 = – Log [H+]
Divide both side by – 1
– 10 = Log [H+]
Take the antilog of – 10
[H+] = antilog (– 10)
[H+] = 1×10¯¹⁰ M
Therefore, the hydrogen ion concentration, [H+] of the Ba(OH)2 solution is 1×10¯¹⁰ M
Answer:
7 moles
Explanation:
The molecular formula of sodium sulfide is Na_2S
One molecule of Sodium sulfide has 2 atoms of sodium and one atom of sulfur
1 mole of Sodium sulfide has 2 moles of sodium and one mole of sulfur
so 3.5 moles of sodium sulfide will have 2× 3.5 moles of sodium atoms
i.e 2×3.5= 7 moles of sodium atom
Kinetic energy due to the movement
