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laiz [17]
3 years ago
15

Four springs are stretched to the same distance from the equilibrium position. The spring constants are listed in the table. A 2

column table with 4 rows. The first column is labeled spring with entries W, X, Y, Z. The second column is labeled spring constant in newtons per meter with entries 24, 35, 22, 15. Which lists the springs based on the amount of elastic potential energy, from greatest to least? X, Y, W, Z X, W, Y, Z Z, W, Y, X Z, Y, W, X
Chemistry
1 answer:
svp [43]3 years ago
9 0

Answer:

The correct option is;

X, W, Y, Z

Explanation:

The parameters given are;

Spring (S),         Spring Constant (N/m)

      W,                   24

      X,                    35

      Y,                    22

      Z,                    15

The equation for elastic potential energy, E_e, is E_e = 0.5 \times k \times x^2

The above equation can also be written as E_e =\dfrac{1}{2}  \times k \times x^2

Where:

k = The spring constant in (N/m)

x = The spring extension

Therefore, since the elastic potential energy, E_e, of the spring is directly proportional to the spring constant, k, we have the springs with higher spring constant will have higher elastic potential energy, E_e, therefore the correct order is as follows;

X > W > Y > Z

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A renowned laboratory reports quadruple-point coordinates of 10.2 Mbar and 24.1°C for four-phase equilibrium of allotropic solid
Inessa [10]

Answer:

The claim is untrue.  

Explanation:

Given the information from the question. We need to evaluate the claim.

According to the phase rule we have F= C-P+2

In this particular situation, the forms are completely allotropic .In order words, they are conjured through the same chemical composition. Thus constituents C= 1, P=4 for four phases and the number variables is 2. As a result, F= C-P+2 =1-4+2= -1. Therefore, the claim is untrue.  

8 0
3 years ago
Determine the molecular formula for each of the following compounds from the
bulgar [2K]

The molecular formula for each of the following compound given the data is

  • C₂H₆
  • C₂H₂
  • C₄H₈Cl₂

<h3>A. How to determine the molecular formula </h3>

We'll begin by calculating the empirical formula. This can be obtained as follow:

  • C = 80%
  • H = 20%
  • Empirical formula =?

Divide by their molar mass

C = 80 / 12 = 6.67

H = 20 / 1 = 20

Divide by the smallest

C = 6.67 / 6.67 = 1

H = 20 / 6.67 = 3

Thus, the empirical formula of the compound CH₃

Thus, the molecular formula of the compound can be obtained as follow

  • Empirical formula = CH₃
  • Molar mass of compound = 30 g/mol
  • Molecular formula =?

Molecular formula = empirical × n = mass number

[CH₃]n = 30

[12 + (3×1)]n = 30

15n = 30

Divide both side by 15

n = 30 / 15

n = 2

Molecular formula = [CH₃]n

Molecular formula = [CH₃]₂

Molecular formula = C₂H₆

Thus, the molecular formula of the compound is C₂H₆

<h3>B. How to determine the molecular formula </h3>

We'll begin by calculating the empirical formula. This can be obtained as follow:

  • C = 92.3%
  • H = 7.7%
  • Empirical formula =?

Divide by their molar mass

C = 92.3 / 12 = 7.7

H = 7.7 / 1 = 7.7

Divide by the smallest

C = 7.7 / 7.7 = 1

H = 7.7 / 7.7 = 1

Thus, the empirical formula of the compound CH

Thus, the molecular formula of the compound can be obtained as follow

  • Empirical formula = CH
  • Molar mass of compound = 26 g/mol
  • Molecular formula =?

Molecular formula = empirical × n = mass number

[CH]n = 26

[12 + 1]n = 26

13n = 26

Divide both side by 13

n = 26 / 13

n = 2

Molecular formula = [CH]n

Molecular formula = [CH]₂

Molecular formula = C₂H₂

Thus, the molecular formula of the compound is C₂H₂

<h3>C. How to determine the molecular formula </h3>

We'll begin by calculating the empirical formula. This can be obtained as follow:

  • C = 37.5%
  • H = 6.3%
  • Cl = 55.8%
  • Empirical formula =?

Divide by their molar mass

C = 37.5 / 12 = 3.125

H = 6.3 / 1 = 6.3

Cl = 55.8 / 35.5 = 1.572

Divide by the smallest

C = 3.125 / 1.572 = 2

H = 6.3 / 1.572 = 4

Cl = 1.572 / 1.572 = 1

Thus, the empirical formula of the compound C₂H₄Cl

Thus, the molecular formula of the compound can be obtained as follow

  • Empirical formula = C₂H₄Cl
  • Molar mass of compound = 127 g/mol
  • Molecular formula =?

Molecular formula = empirical × n = mass number

[C₂H₄Cl]n = 127

[(2×12) + (4×1) + 35.5]n = 127

63.5n = 127

Divide both side by 63.5

n = 127 / 63.5

n = 2

Molecular formula = [C₂H₄Cl]n

Molecular formula = [C₂H₄Cl]₂

Molecular formula = C₄H₈Cl₂

Thus, the molecular formula of the compound is C₄H₈Cl₂

Learn more about empirical formula:

brainly.com/question/24297883

#SPJ1

7 0
2 years ago
Which statement is true about this reaction?
ipn [44]

Answer:

C-Its product is heavier than each of its reactants.

Explanation:

Correct equation:

               ¹⁴₇N + ¹₁H → ¹⁵₈O

In the reaction above, we can conclude within the given conditions of the reaction that the product formed is heavier than the reactants.

The product is oxygen with a mass number of 15 as shown by the superscript preceeding the symbol of the atom.

The reactants are:

       Nitrogen, N with a mass number of 14

      Hydrogen, H with a mass number of 1

The mass number is a true reflection of the mass of an atom. It clearly shows the mass of the nucleons which are the most massive particles that makes up an atom. The nucleons are protons and neutrons that makes up the tiny nucleus of the atom.

Oxygen here has more nucleons that each of Nitrogen and Hydrogen.

6 0
3 years ago
Read 2 more answers
If I have a 78c and I fail a test that’s worth 15% of my grade what would it drop to ?
koban [17]
Depends on the grade of the test. But for the most part if it’s below a 78, it’ll drop, If it’s above it’ll raise. It shouldn’t drop or raise it more than 3 point/percent.
8 0
3 years ago
A 3.50 amp power supply is used to deposit chromium from a solution of CrCl3. How long will it take to deposit 100.0 grams of ch
Norma-Jean [14]

Explanation:

The given data is as follows.

   Current (I) = 3.50 amp,        Mass deposited = 100.0 g

  Molar mass of Cr = 52 g

It is known that 1 faraday of electricity will deposit 1 mole of chromium. As 1 faraday means 96500 C and 1 mole of Cr means 52 g.

Therefore, 100 g of Cr will be deposited by "z" grams of electricity.

                z \times 52 g = 96500 \times 100 g

                         z = \frac{96500 \times 100 g}{52 g}

                            = 185576.9 C

As we know that, Q = I × t

Hence, putting the given values into the above equation as follows.

                      Q = I × t

           185576.9 C = 3.50 amp \times t  

                      t = 53021.9 sec

Thus, we can conclude that 100 g of Cr will be deposited in 53021.9 sec.

3 0
3 years ago
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