Answer:
Explanation:
The capacitor of a parallel-plate capacitor is given by:
where
A is the area of each plate
d is the separation between the plates
is the vacuum permittivity
The energy stored in a capacitor instead is given by
where
Q is the charge stored in each plate
Substituting the expression we found for C inside the last formula,
And re-arranging it
Now if we substitute
We find the charge stored on the capacitor:
Answer:
(a) 1.58 V
(b) 0.0126 Wb
(c) 0.0493 V
Solution:
As per the question:
No. of turns in the coil, N = 400 turns
Self Inductance of the coil, L = 7.50 mH =
Current in the coil, i = A
where
Now,
(a) To calculate the maximum emf:
We know that maximum emf induced in the coil is given by:
For maximum emf, should be maximum, i.e., 1
Now, the magnitude of the maximum emf is given by:
(b) To calculate the maximum average flux,we know that:
(c) To calculate the magnitude of the induced emf at t = 0.0180 s: