So he has 7 sheepleft if i did it correctly
15-8=7
Answer:
Therefore,
The potential (in V) near its surface is 186.13 Volt.
Explanation:
Given:
Diameter of sphere,
d= 0.29 cm


Charge ,

To Find:
Electric potential , V = ?
Solution:
Electric Potential at point surface is given as,

Where,
V= Electric potential,
ε0 = permeability free space = 8.85 × 10–12 F/m
Q = Charge
r = Radius
Substituting the values we get


Therefore,
The potential (in V) near its surface is 186.13 Volt.
Answer:
a) <em>473.33 nm
</em>
<em>b) 568 nm</em><em> and </em><em>406 nm</em>
<em>c) </em>bluish green and blue
Explanation:
a) As the light traverses the layer of oil it first reflects at the front surface of the oil. Here the index of refraction increases from that of air to that of the oil , so a phase change occurs. The light then reflects from the rear surface of oil. The index of refraction increases from that of the oil to that of the glass , so again a phase change occurs. Thus two phase changes occur.
In thin-film interference with 0 or 2 phase changes, condition for constructive interference is:
2t=mλ/n
So:
λ=
2tn/m
<em><u>For m=1</u></em>
λ=1420 nm
<em><u>For m=2</u></em>
λ=710 nm
<em><u>For m=3</u></em>
λ=473.33 nm
<em><u>For m=4</u></em>
λ=355 nm
<em>Thus the only wavelength in the visible spectrum </em><em>(400 - 700 nm)</em><em> that will give constructive interference is </em><em>473.33 nm
</em>
b)
In thin-film interference with 0 or 2 phase changes, condition for destructive interference is:
2t=(m+1/2)λ/n=(2m+1)*λ/2n
so;
λ=4tn/(2m+1)
<em><u>For m=1</u></em>
λ=946.667 nm
<em><u>For m=2</u></em>
λ=568 nm
<em><u>For m=3</u></em>
λ=405.33 nm
<em><u>For m=4</u></em>
λ=315.56 nm
<em>Thus the wavelengths in the visible spectrum (</em><em>400 to 700 nm)</em><em> that will give destructive interference are </em><em>568 nm</em><em> and </em><em>406 nm</em>
<em>c) </em>The color of reflected light is bluish green since the wavelength is 473.3 nm . We know that the colors of reflected and transmitted light are complimentary to each other.Thus the color of transmitted light is blue (due to the combination of wavelengths 568 nm (green) and 406 nm (deep violet).
<em />
Complete question:
A force F is applied to the block as shown (check attached image). With an applied force of 1.5 N, the block moves with a constant velocity.
Approximately what applied force is needed to keep the box moving with a constant velocity that is twice as fast as before? Explain
Answer:
The applied force that is needed to keep the box moving with a constant velocity that is twice as fast as before, is 3 N
Force is directly proportional to velocity, to keep the box moving at the double of initial constant velocity, we must also double the value of the initially applied force.
Explanation:
Given;
magnitude of applied force, F = 1.5 N
Apply Newton's second law of motion;
F = ma

The applied force needed to keep the box moving with a constant velocity that is twice as fast as before;

Therefore, the applied force that is needed to keep the box moving with a constant velocity that is twice as fast as before, is 3 N
Force is directly proportional to velocity, to keep the box moving at the double of initial constant velocity, we must also double the value of the applied force.