Question

A 0.907 mole sample of ideal gas at 12c occupies a volume of 4.25L. What is the pressure of gas?

Answer 1

Pressure of the ideal gas=505.7kPa

Given:

No of moles=0.907mole

Temperature of the gas=$12^{\circ} \mathrm{C}$

Volume of the gas=4.25L

To find:

Pressure of the gas

Step by Step Explanation:

Solution:

According to the ideal gas equation

$P V=n R T$ and from this pressure is derived as

$P=\frac{n R T}{V}$

Where P=Pressure of the gas

V=Volume of the gas=4.25L

n=No of the moles=0.907mole

R=Gas constant=8.314$J / m o l^{-1} K^{-1}$

T=Temperature of the gas=$12^{\circ} \mathrm{C}$ =273+12=285K

Substitute these known values in the above equation we get

$P=\frac{0.907 \times 8.314 \times 285}{4.25}$

$P=\frac{2149.13}{4.25}$

P=505.7kPa

Result:

Thus the pressure of the ideal gas is 505.7kPa