Pressure of the ideal gas=505.7kPa
Given:
No of moles=0.907mole
Temperature of the gas=
Volume of the gas=4.25L
To find:
Pressure of the gas
<u>Step by Step Explanation:
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Solution:
According to the ideal gas equation
and from this pressure is derived as

Where P=Pressure of the gas
V=Volume of the gas=4.25L
n=No of the moles=0.907mole
R=Gas constant=8.314
T=Temperature of the gas=
=273+12=285K
Substitute these known values in the above equation we get

P=505.7kPa
Result:
Thus the pressure of the ideal gas is 505.7kPa