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Archy [21]
3 years ago
12

The name given to the substance formed when a liquid is miscible in another liquid.

Chemistry
1 answer:
m_a_m_a [10]3 years ago
5 0

Answer:

Solute

Explanation:

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How many moles of ions are released when 0.27 mole of cobalt chloride is dissolved in water?
egoroff_w [7]

0.81 moles

Explanation:

cobalt chloride when dissolved in water dissociate into cobalt and chloride ions as shown;

CoCl₂ (s) → [Co²⁺](aq) + 2[Cl⁻] (aq)

The mole ratio between CoCl₂ and [Co²⁺] is 1 ; 1 while the mole ratio between CoCl₂ and [Cl⁻] is 1 : 2

Therefore; 0.27 moles of CoCl₂ will form;

(1 * 0.27) = 0.27 moles of [Co²⁺] ions

(2 * 0.27) = 0.54 moles of [Cl⁻] ions

Total moles of dissociated ions are;

0.27 + 0.54

= 0.81 moles

4 0
3 years ago
Which change is most likely to occur when a molecule of h2 and a molecule i2 collide with proper orientation and sufficient ener
Alekssandra [29.7K]

Answer: Formation of hydrogen iodide will occur.

Explanation:

When molecule of hydrogen gas (H_2) and molecule of iodine gas (I_2) collide with proper orientation and with sufficient amount of energy. This collision of the two different molecules of gases will result in the formation of hydrogen iodide.

The balanced chemical equation of the reaction will written as:

H_2(g)+I_2(g)\righarrow 2HI(g)

6 0
4 years ago
Read 2 more answers
I will mark brainliest
Veronika [31]

I believe the answer is B??????????? Hope this helps

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5 0
3 years ago
Read 2 more answers
A chemistry graduate student is studying the rate of this reaction:
sashaice [31]

Answer:

Explanation:

Attached below is the solution

6 0
3 years ago
How much energy is lost to condense 300. grams of steam at 100.C?
True [87]

Energy lost to condense = 803.4 kJ

<h3>Further explanation</h3>

Condensation of steam through 2 stages:

1. phase change(steam to water)

2. cool down(100 to 0 C)

1. phase change(condensation)

Lv==latent heat of vaporization for water=2260 J/g

\tt Q=300\times 2260=678000~J

2. cool down

c=specific heat for water=4.18 J/g C

\tt Q=300\times 4.18\times (100-0)=125400

Total heat =

\tt 678000+125400=803400~J

3 0
3 years ago
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