A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the
KM² = KE² + ME²KM² = 8² + (3√5)² = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM) = 1/2 * 3√5 * (40 + 24) = 1/2 * 3√5 * 64 = 3 x 2.23 * 32 = 214.66 units²
16000000000000.
Hope it helped
Answer:
The current of the water is 1.714 mph.
Step-by-step explanation:
Let the boat in t hours can travel 18 miles upstream, and 24 miles downstream.
Therefore, if the speed of the boat in still water is 12 mph and that of water is x mph , then we can write
........ (1) and
............ (2)
Now, adding those two equations (1) and (2) we get,
⇒ t = 1.75 hours.
Now, from equation (1) we get
⇒ x = 1.714 mph
Therefore, the current of the water is 1.714 mph. (Answer)
Answer:
-32 degrees
Step-by-step explanation:
Okay so-
8 x 4 = 32
0 - 32 = -32
-32 degrees Fahrenheit
