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svetoff [14.1K]
2 years ago
14

Suppose 3 neutrons are released by an atom of U-235 in the first stage of a fission chain reaction. Each of these neutrons has e

nough energy to cause another fission reaction in another nucleus of U-235, releasing more neutrons. And if all of those 2nd stage neutrons cause other nuclei to fission in a 3rd stage, how many total U-235 atoms will have undergone fission after these 3 stages of the chain reaction?
A. 27
B. 9
C. 11
D. 12
Physics
2 answers:
8090 [49]2 years ago
5 0
Is not A.) 27 don't know the answer but it is not (A)
DIA [1.3K]2 years ago
4 0
The answer is A.) 27<span />
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The electric potential in a region of space is \[V=350/\sqrt{x ^{2}+y ^{2}}\] where x and y are in meters. what is the strength
VARVARA [1.3K]
So the given value or the formula in getting the electric potential region of space is V=350/sqrt of x^2+y^2. So the given data is x and y is equals to 2.6 and 2.8. So in my calculation i came up with an answer of 91.6
8 0
3 years ago
The length of aluminum rods produced by a company are approximated by a Gaussian distribution with a mean of 10 cm and a standar
ExtremeBDS [4]

Given Information:

Mean length of aluminum rods = μ = 10 cm

Standard deviation of length of aluminum rods = σ = 0.02 cm

Required Information:

a) P(9.98 < X < 10.02) = ?

b) P(9.90 < X < 10.1) = ?

Answer:

a) P(9.98 < X < 10.02) = 68.27%

b) P(9.90 < X < 10.1) = 100%

Explanation:

What is Normal Distribution?

Normal Distribution or also known as Gaussian Distribution, is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability

a) We want to find out the probability that the length of aluminum rods is between 9.98 and 10.02 cm.

P(9.98 < X < 10.02) = P( \frac{x - \mu}{\sigma} < Z < \frac{x - \mu}{\sigma} )\\\\P(9.98 < X < 10.02) = P( \frac{9.98- 10}{0.02} < Z < \frac{10.02 - 10}{0.02} )\\\\P(9.98 < X < 10.02) = P( \frac{-0.02}{0.02} < Z < \frac{0.02}{0.02} )\\\\P(9.98 < X < 10.02) = P( -1 < Z < 1 )\\\\

The z-score corresponding to -1 is 0.15866 and 1 is 0.84134

P(9.98 < X < 10.02) = P( Z < 1 ) - P( Z < -1 ) \\\\P(9.98 < X < 10.02) = 0.84134 - 0.15866 \\\\P(9.98 < X < 10.02) = 0.6827\\\\P(9.98 < X < 10.02) = 68.27 \%

Therefore, the probability that the length of aluminum rods is between 9.98 and 10.02 cm is 68.27%

b) We want to find out the probability that the length of aluminum rods is between 9.90 and 10.1 cm.

P(9.90 < X < 10.1) = P( \frac{x - \mu}{\sigma} < Z < \frac{x - \mu}{\sigma} )\\\\P(9.90 < X < 10.1) = P( \frac{9.90- 10}{0.02} < Z < \frac{10.1 - 10}{0.02} )\\\\P(9.90 < X < 10.1) = P( \frac{-0.1}{0.02} < Z < \frac{0.1}{0.02} )\\\\P(9.90 < X < 10.1) = P( -5 < Z < 5 )\\\\

The z-score corresponding to -5 is 0 and 5 is 1

P(9.90 < X < 10.1) = P( Z < 5 ) - P( Z < -5 ) \\\\P(9.90 < X < 10.1) = 1 - 0 \\\\P(9.90 < X < 10.1) = 1\\\\P(9.90 < X < 10.1) = 100 \%

Therefore, the probability that the length of aluminum rods is between 9.90 and 10.1 cm is 100%

How to use z-table?

Step 1:

In the z-table, find the two-digit number on the left side corresponding to your z-score. (e.g 1.0, 2.2, 0.5 etc.)

Step 2:

Then look up at the top of z-table to find the remaining decimal point in the range of 0.00 to 0.09. (e.g. if you are looking for 1.00 then go for 0.00 column)

Step 3:

Finally, find the corresponding probability from the z-table at the intersection of step 1 and step 2.

8 0
3 years ago
A laser source has a bandwidth of 30GHz (a) Calculate the coherence length of the source b) What is the time separation of secti
abruzzese [7]

Explanation:

It is given that,

Bandwidth of a laser source, f=30\ GHz=30\times 10^9\ Hz

(b) Let t is the time separation of sections of sections of the light wave that can still interfere. The time period is given by :

T=\dfrac{1}{f}

T=\dfrac{1}{30\times 10^9}

T=3.33\times 10^{-11}\ s

(a) Let h is the coherence length of the source. It is given by :

l=c\times T

c is the speed of light

l=3\times 10^8\times 3.33\times 10^{-11}

l = 0.0099 m

Hence, this is the required solution.

6 0
2 years ago
Jason applies a force of 4.00 newtons to a sled at an angle 62.0 degrees from the ground. What is the component of force effecti
Andreas93 [3]
Answer: 1.88 N

Explanation:

Data:

Force = 4.00N
angle = 62°
horizontal force = ?

Solution:

The trigonometric ratio that relates horizontal - leg to hypotenuse is the cosine.

That ratio is:

                        horizontal - leg
cos(angle) = -------------------------
                          hypotenuse

So, applied to the force, that is:

                             horizontal force
cos (angle) = -----------------------------------
                                 total force

So, clearing the horizontal component you get:
                                         
horizontal force = force * cos (angle)

Substitute the data given:

horizontal force = 4.00N * cos(62°) = 4.00N * 0.4695 = 1.88 N

Answer: 1.88N


7 0
2 years ago
Read 2 more answers
I. How does The Bhutan Forest Act of 1969, affect the lives of shifting cultivators?​
ZanzabumX [31]

The Bhutan Forest Act of 1969, affect the lives of shifting cultivators because the act placed the status of Tsheri land on the same footing with wetland and rain-fed land.

<h3>What is shifting cultivators?</h3>

A field that had been developed whenever was left neglected for quite a long time, Shifting cultivators were tracked down in the sloping and forested lots of North-east and Central India. The existences of these ancestral individuals relied upon free development inside backwoods and on having the option to involve the land and woods for developing their harvests.

The Forest Act of 1969 has restricted new clearances for moving development however has not deterred the act of it where such development doesn't jeopardize the wellbeing of the roadway and public property. The Land Act of 1979 has put the situation with
Tsheri land on a similar footing with wetland and rain fed land.

Thus, Bhutan Forest Act of 1969, affect the lives of shifting cultivators.

Learn more about shifting cultivators

brainly.com/question/7945312

#SPJ1

8 0
1 year ago
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