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prisoha [69]
4 years ago
7

How does mass and distance affect gravitational force?

Physics
1 answer:
loris [4]4 years ago
4 0

Answer:

It shows that the gravitational force is directly proportional to the product of masses of two bodies and inversely proportional to the square of distance between them, So, as the mass of bodies increases, the gravitational force increases and with the increase of distance between them, the gravitational force decreases.

Explanation:

You might be interested in
An electric field with a magnitude of 6.0 × 104 N/C is directed parallel to the positive y axis. A particle with a charge q = 4.
jekas [21]

Answer:

Electric force, F=2.88\times 10^{-14}\ N

Explanation:

It is given that,

Magnitude of electric field, E=6\times 10^4\ N/C

Charge, q=4.8\times 10^{-19}\ C

The electric field is directed parallel to the positive y axis. We need to find the  force on the charge particle. It is given by :

F=q\times E

F=4.8\times 10^{-19}\ C\times 6\times 10^4\ N/C

F=2.88\times 10^{-14}\ N

So, the electric force on the charge is 2.88\times 10^{-14}\ N. Hence, this is the required solution.

5 0
4 years ago
What is the power of an electric with a current of 0.5 A and a voltage of 120 V ? The formula for power is P =IV
zaharov [31]

Answer:

60Watts

Explanation:

Given parameters:

Current = 0.5A

Voltage  = 120V

Unknown

Power = ?

Solution:

The power in the electric circuit is the product of current and voltage;

      P = IV

Insert the given parameters and solve;

      P = 0.5 x 120

      P  = 60Watts

7 0
3 years ago
Read 2 more answers
Fluids can flow and change shape to fit their containers. Which two states are<br> fluids?
mr_godi [17]

Answer: the two states that are fluid are;-

<u>#{1} liquid</u>

<u>#{2} gas </u>

Explanation:

as we know that there are mainly three states of substance

but among them only two of them can fluid and takes the shape of the container that are liquid and gas

4 0
3 years ago
Simplified. The absorption spectra of ions have been used to identify the presence of the elements in the atmospheres of the sun
Nookie1986 [14]

Answer:

The answer is "3.83 \times 10^9 \ m"

Explanation:

Z=2, so the equation is E= \frac{-4B}{n^2}

Calculate the value for E when:  

n=2 and n=9

The energy is the difference in transformation, name the energy delta E Deduct these two energies  

In this transition, the wavelength of the photon emitted is:

\Delta E=2.18 \times  10^{-18} ( \frac{1}{4}- \frac{1}{81})

\lambda = \frac{h c}{\Delta E}

h ( Planck's\  constant) = 6.62 \times  10^{(-34)} \ Js \\\\ speed \ of \ light = 3 \times 10^{8} \ \frac{m}{s}\\\\= \frac{6.62 \times 10^{(-34)} \times 3 \times 10^ {8}}{2.18 \times  10^{-18}} (\frac{1}{4}- \frac{1}{81}) \\\\=3.83 \times 10^9 \ m\\\\

6 0
3 years ago
If the 78.0 kg astronaut were in a spacecraft 6R from the center of the earth, what would the astronaut's weight be on earth? 76
den301095 [7]

(a) 764.4 N

The weight of the astronaut on Earth is given by:

F=mg

where

m is the astronaut's mass

g is the acceleration due to gravity

Here we have

m = 78.0 kg

g = 9.8 m/s^2 at the Earth's surface

So the weight of the astronaut is

F=(78.0)(9.8)=764.4 N

(b) 21.1 N

The spacecraft is located at a distance of

r=6R

from the center of Earth.

The acceleration due to gravity at a generic distance r from the Earth's center is

g=\frac{GM}{r^2}

where G is the gravitational constant and M is the Earth's mass.

We know that at a distance of r = R (at the Earth's surface) the value of g is 9.8 m/s^2, so we can write:

GM=9.8R^2 (1)

the acceleration due to gravity at r=6R instead will be

g'=\frac{GM}{(6R)^2}

And substituting (1) into this formula,

g'=\frac{9.8R^2}{36R^2}=0.27 m/s^2

So the weight of the astronaut at the spacecratf location is

F'=mg'=(78.0 kg)(0.27 m/s^2)=21.1 N

6 0
4 years ago
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