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2 years ago

Match each term to its description.

Chemistry

1 answer:

stepladder [879]2 years ago

8 0

Based on ecological studies, the definitions below applies to the given terms:

Peak phenomena: this is when a population grows at a fast rate, then quickly drops when the resources run out
Biological surplus: this occurs when there are more organisms in a population than the ecosystem can sustain
Climax community: this is a point in an ecosystem when all populations reach a point of little or no change
Sigmoid phenomena: this is when a population increases while food and habitat are abundant and decreases as food becomes less available

<h3>What is ecology and what are some terms in ecology?</h3>

Ecology is the study of living things and their interactions with their environment.

Some terms in ecology include:

Peak phenomena: this is when a population grows at a fast rate, then quickly drops when the resources run out
Biological surplus: this occurs when there are more organisms in a population than the ecosystem can sustain
Climax community: this is a point in an ecosystem when all populations reach a point of little or no change
Sigmoid phenomena: this is when a population increases while food and habitat are abundant and decreases as food becomes less available

Learn more about Peak phenomena, Biological surplus, Climax community and Sigmoid phenomena at: brainly.com/question/7149100

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Which of these has the most covalent character? <br> NaF Caf2 Bef2 CsF SrF2

Ksenya-84 [330]

Thus BeF2 is of most covalent character.

Anyways, covalent/ionic character is a bit tricky to figure out; we measure the difference in electronegativity of two elements bonding together and we use the following rule of thumb: if the charge is 0 (or a little more), the bond is non-polar covalent; if the charge is > 0 but < 2.0 (some references say 1.7), the bond is polar covalent; if the charge is > 2.0 then the bond is ionic. Covalent character refers to smaller electronegativity difference while ionic character refers to greater electronegativity difference.

Now, notice all of our bonds are with F, fluorine, which has the highest electronegativity of 3.98. This means that to determine character we need to consider the electronegativities of the other elements -- whichever has the greatest electronegativity has the least difference and most covalent character.
Na, sodium, has electronegativity of 0.93, so our difference is ~3 -- meaning our bond is ionic. Ca, calcium, has 1.00, leaving our difference to again be ~3 and therefore the bond is ionic. Be, beryllium, has 1.57 yielding a difference of ~2.5, meaning we're still dealing with ionic bond. Cs, cesium, has 0.79, meaning our difference is again ~3 and therefore again our compound is of ionic bond. Lastly, we have Sr, strontium, with an electronegativity of 0.95 and therefore again a difference of roughly 3 and an ionic bond. <span>
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2 years ago

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Zn2+, Ni4+, F-

hram777 [196]

Ionic compounds are formed between oppositely charged ions.

A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.

First empirical formula of binary ionic compound is written between $Zn^{2+} (Positive ion)and F^{-} (Negative ion)$

First Formula would be $ZnF_{2}$

Second empirical formula is between $Zn^{2+}(Positive ion) and O^{2-}(Negative ion)$

Second Formula would be $Zn_{2}O_{2}$

Note : When the subscript are same they get cancel out, so $Zn_{2}O_{2}$ would be written as $ZnO$

Third empirical formula is between $Ni^{4+}(Positive ion) and F^{-}(Negative ion)$

Third Formula would be : $NiF_{4}$

Forth empirical formula is between $Ni^{4+}(Positive ion)and O^{2-}(negative ion)$

Forth Formula would be : $Ni_{2}O_{4}$ or $NiO_{2}$

Note- The subscript will be simplified and the formula will be written as $NiO_{2}$ .

The empirical formula of four binary ionic compounds are : $ZnF_{2}, ZnO, NiF_{4},NiO_{2}$

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2 years ago

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