Answer:
pH = 2.059
Explanation:
At the Cathode:
The reduction reaction is:
At the anode:
At oxidation reaction is:
The overall equation for the reaction is:
The overall cell potential is:
Using the formula for the Nernst equation:
where;
E = 0.66
(Zn^2+)=0.22 M
Then
![0.66 =0.76- ( \dfrac{0.0591}{2})log \bigg ( \dfrac{[Zn^{2+} ] PH_2}{[H^+]^2} \bigg )](https://tex.z-dn.net/?f=0.66%20%3D0.76-%20%28%20%5Cdfrac%7B0.0591%7D%7B2%7D%29log%20%5Cbigg%20%28%20%5Cdfrac%7B%5BZn%5E%7B2%2B%7D%20%5D%20PH_2%7D%7B%5BH%5E%2B%5D%5E2%7D%20%5Cbigg%20%29)
![0.66 =0.76- 0.02955 * log \bigg ( \dfrac{0.22*0.87}{[H^+]^2} \bigg )](https://tex.z-dn.net/?f=0.66%20%3D0.76-%200.02955%20%2A%20log%20%5Cbigg%20%28%20%5Cdfrac%7B0.22%2A0.87%7D%7B%5BH%5E%2B%5D%5E2%7D%20%5Cbigg%20%29)
3.4 = log ( 0.1914) - 2 log [H⁺]
3.4 = -0.7180 - 2 log [H⁺]
3.4 + 0.7180 = - 2 log [H⁺]
4.118 = - 2 log [H⁺]
pH = log [H⁺] = 4.118/2
pH = 2.059
Answer:
D or A
<em>But I do know...</em>
It's because new strains of the virus are constantly appearing and evolving, so the vaccine must change along with them.
The problem can solved using the heat equation which is expressed as:
H = mCΔT
where H is the energy absorbed or released, m is the mass of the substance, C is the specific heat capacity, and ΔT is the change in temperature.
2208 J = 41 g x 4.18 J/g·°C x ( T - 24 °C)
T = 36.88 °C
Answer:
NH3(g) + H2O(1) → NH4+(aq) + OH (aq)
HF(aq) + H2O(1) → H3O+(aq) + F (aq)
Explanation:
Acid-base reactions are chemical reactions involving acids and bases. Acids tend to ionize/dissociate in water, a property which determines their strength. Ionization of an acid refers to the acid losing its hydrogen ion (H+) in water solution. An acid ionizes or dissociates to form a conjugate base.
A strong acid is so because it ionizes completely in water i.e. loses all its hydrogen ion (H+) while a weak acid partially ionizes in water.
In the chemical reactions;
1) NH3(g) + H2O(1) → NH4+(aq) + OH (aq)
H20 loses its hydrogen ion (H+) in this reaction to form an anion (OH-). Hence, water (H20) is an acid in this case which ionizes to form a conjugate base (OH-). This is an example of ionization of acid.
2) HF(aq) + H2O(1) → H3O+(aq) + F (aq)
Hydrogen fluoride (HF) loses its hydrogen ion (H+) in the presence of water to form anion (F-). The HF is the acid while F- is it's conjugate base. Thus, an example of ionization of acid
