Answer:
Explanation:
Given
Required
Determine the percentage error
First, we need to determine the difference in the measurement
The percentage error is calculated as thus:
<em>approximated</em>
So the equation is balanced, meaning they have the smallest amounts of each element in the reactants to create the products.
So, 2 moles of H2S (the coefficient) contributes to 2 moles Ag2S, which is why the ratio is 2:2.
I hope that made sense.
<span>mg = 2.42 g
Tg = 72.2 deg.C
mw = 15.8 g
Tw = 24.5
Tf = 27 deg. C
Cw = 4.18 J/g. deg. C
Energy balance for insulated system,
ΔE = 0
ΔUw + ΔUg = 0
ΔUw = - ΔUg
Qin = Qout
mg*cg*ΔTg = mw*cw*ΔTw
2.42*cg*(72.2 - 27) = 15.8*4.18*(27 - 24.5)
cg = 1.5095 J/g. deg.C or 1.5095 J/g.K</span><span>
</span>
Answer:
The amount of heat required to vaporize 2.58 kg of water at its boiling point is 5,830.8 kJ.
Explanation:
A substance undergoes a change in temperature when it absorbs or gives up heat to the environment around it. However, when a substance changes phase it absorbs or gives up heat without causing a change in temperature. The heat Q that is necessary for a mass m of a certain substance to change phase is equal to:
Q = m*L
where L is called the latent heat of the substance.
In this case:
- m=2.58 kg
- The heat of vaporization of water is L=2260*10³ J/kg
Replacing:
Q= 2.58 kg* 2260*10³ J/kg
Q= 5,830,800 J = 5,830.8 kJ (Being 1,000 J= 1 kJ)
<u><em>The amount of heat required to vaporize 2.58 kg of water at its boiling point is 5,830.8 kJ.</em></u>
