All categories

4 years ago

Define radioactivity and write down properties of radioactive Ray's

Chemistry

2 answers:

BlackZzzverrR [31]4 years ago

6 0

Answer:

Explanation:

So basically is just explain what radioacitvity and then radidoactive

Radioactivity is the spontaneous release of energy from an unstable atom to get to a more stable state. Ionizing Radiation is the energy that comes out of a radioactive atom. Radioactive isotopes are radioactive atoms of the same element that have different numbers of neutrons.

chubhunter [2.5K]4 years ago

4 0

Answer:

❤❤❤❤❤❤

Explanation:

You might be interested in

If a solution conducts electricity, it it positive evidence that

Goshia [24]

If a solution conducts electricity, it it positive evidence that solute dissolved in solvent is electrolyte.

7 0

3 years ago

Read 2 more answers

2.3 Zinc has five naturally occurring isotopes: 48.63% of 64 Zn with an atomic weight of 63.929 amu; 27.90% of 66Zn with an atom

lakkis [162]

Answer: The average atomic mass of element Zinc is 65.40 amu.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

For $_{30}^{64}\textrm{Zn}$ isotope:

Mass of $_{30}^{64}\textrm{Zn}$ isotope = 63.929 amu

Percentage abundance of $_{30}^{64}\textrm{Zn}$ isotope = 48.63 %

Fractional abundance of $_{30}^{64}\textrm{Zn}$ isotope = 0.4863

For $_{30}^{66}\textrm{Zn}$ isotope:

Mass of $_{30}^{66}\textrm{Zn}$ isotope = 65.926 amu

Percentage abundance of $_{30}^{66}\textrm{Zn}$ isotope = 27.90 %

Fractional abundance of $_{30}^{66}\textrm{Zn}$ isotope = 0.2790

For $_{30}^{67}\textrm{Zn}$ isotope:

Mass of $_{30}^{67}\textrm{Zn}$ isotope = 66.927 amu

Percentage abundance of $_{30}^{67}\textrm{Zn}$ isotope = 4.10 %

Fractional abundance of $_{30}^{67}\textrm{Zn}$ isotope = 0.0410

For $_{30}^{68}\textrm{Zn}$ isotope:

Mass of $_{30}^{68}\textrm{Zn}$ isotope = 67.925 amu

Percentage abundance of $_{30}^{68}\textrm{Zn}$ isotope = 18.75 %

Fractional abundance of $_{30}^{68}\textrm{Zn}$ isotope = 0.1875

For $_{30}^{70}\textrm{Zn}$ isotope:

Mass of $_{30}^{70}\textrm{Zn}$ isotope = 69.925 amu

Percentage abundance of $_{30}^{70}\textrm{Zn}$ isotope = 0.62 %

Fractional abundance of $_{30}^{70}\textrm{Zn}$ isotope = 0.0062

Putting values in equation 1, we get:

$\text{Average atomic mass of Zinc}=[(63.929\times 0.4863)+(65.926\times 0.2790)+(66.927\times 0.0410)+(67.925\times 0.1875)+(69.925\times 0.0062)]$

$\text{Average atomic mass of Zinc}=65.40amu$

Hence, the average atomic mass of element Zinc is 65.40 amu.

7 0

4 years ago

I find that there are 500 atoms of U-235 and 1500 atoms of Pb-207. If we assume the mineral contained only parent and no daughte

swat32

Explanation:

From the question it can be infered that initially only parent atoms were present in the rock and no daughter atom. So, initially there was only uranium atom and no lead atom. So, in total there were 500+1500= 2000 uranium atom. And no lead tom was there.

3 0

4 years ago

4g of calcium metal is burned in oxygen of air to form calcium oxide. (Ca = 40, O= 16, at STP: 32g of oxygen has 22.4L)

Alexus [3.1K]

Answer:

m=4 g Ca

M=ArCa+ArO=56 g/mol

Ca+O2-2CaO

nCa= m/M= 4/40=0.1 moles of Ca

the ratio of moles: 1 mole Ca:2 moles CaO

0.1 moles Ca =0.2 moles CaO

n=m/M

m=n×M

m=0.2×56=11.2 g CaO

3 0

2 years ago

For the reaction 2 A - Products, the concentration of A is monitored over time. A graph of [A] versus time was found to be linea

GaryK [48]

Answer:

none of these statements is true

8 0

3 years ago